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Hi All,

How to pass variable inside expect script ?

expect -c ' <need to pass $var here> interact'

Please help me out

Thanks in advance,
Renjesh

Hi All,

I have a expect script which is working for single server, but if i am trying to pass value of the variable inside expect, it is not working. Please see below :-
expect -c 'spawn ssh...

I have script which send a mail with top output. The script look like
$ cat health.sh
#!/bin/sh
maillist="email address"
rm /home/rtq1/file
top -n 1 | head 15 > file
cat file | mailx -s "Daily...

No. Passwordless login will not allow in my test servers

Hello All,

I am trying a shell script for automatically login to test servers and pulling the output of top command from all using expect.

----snippet of code ---
#!/usr/bin/expect -f...

what happened ?

Here is the code :-

choice=""
tgtser=""
function menu
{
clear
echo "-------------------------------------------------------"
echo " * * * * * * * Subversion Main Menu * * * * * *...

Hello All,

I have code as follows :-
while true do
[calling a function]
{opening a case1 statement}
1)
[Calling another function]
{opening another case2 statement} ...

Thank you for your help ...

I will show the entire code and then probably you can help me ..

# Ver Date Description Analyst
# --- ---- ----------- -------
# A01 09/08/11 ...

Thank you for your help ...

I don't want to call another function for doing this ..
Is there something like "goto" command in which i can move the flow of the script ?

I have menu option in my script and in that i have 4 options like below :-

echo "Please select a target server .."
echo "[1] AIX - AIX1"
echo "[2] AIX - AIX2"
echo...

This will work if the pattern is not continous. But XML is not coming as line by line. Like below :-

<RequestBillsRsp...

Hi All,

i have an XML file like :-

<RequestBillsRsp...

DIR :- location form there i want to take backup(both files and directory needed)

DEST :- Location where i need the backed files

What ever is there in Array, i need to copy whether it is a file...

I have an interesting requirement. I have declaried an array like :-
arr=`find . ! -name "." | xargs -I {} echo {} | cut -c 2-${#}`

Then i will try to access the array elements like :-
i=0
for...

I want to do something like

if pattern found

do something
else

do something
...

I have to grep a pattern. scenario is like :-

Suppose "/etc/sec/one" is a string, i need to check if this string contains "one" using any utility


something like

if /etc/sec/one | grep ;...

Yes, it is working ...

Thanks a lot

I will clarify a little more with an example

I have two strings ..

/opt/src/deafult.cfg and /opt/src/esr/common/test1

From this i want only "default.cfg" and "test1" ...

Note :- it is...

In shell scripting

I have a string something like "/opt/src/default.cfg" OR /opt/src/common/one

This whole string stored in an array. The problem is this string is not constant and it will keep on changing as lot of...

Hi All,

it is working fine now ...
set -A arr `find . ! -name "." | xargs -I {} echo {} | cut -c 2-${#}`

This works for me ..

Thanks a lot
Renjesh

Now it is working, but "." is still there with the output. I want to remove the "." then store data in array.
$ ./test.sh
./two

If i put that (), it is throwing a syntax error .. :confused:
$ ./test.sh
./test.sh[2]: Syntax error at line 2 : `(' is not expected.