Search Results

finding the common items can be done using two ways

fgrep -f file1 file2

or

awk 'NR==FNR{a[$1]=$1;next} a[$1]' file1 file2

yes, it can be done in similar way, use -v for every variables passed.
awk -F\| -v date=$v_date1 -v file=$filename 'NF==4{ print $0>date;next} NF!=4 {print $0 >file;next}' test1.txt

You need to send the value of the variable using -v option to awk

awk -F\| -v date=$v_date1 'NF==4{ print $0>date;next} NF!=4 {print $0 >"murali.txt";next}' test1.txt

This may help

ema=`echo "(${currentprice} * 0.153846154) + (${previousema} * (1 - 0.153846154))" | bc`

Thanks methyl for the correction, i missed the top 10 part.
Just a change in your one liner


du -k apps | sed '$d' | sort -nr | head -10


-sk will give the total sum, sed to delete the total...

This may help using shell script.

du -k apps > temp
sed '$d' temp > temp1
mv temp1 temp
awk '$1>max {max=$1;val=$2} END {print max, val}' temp

Please use backquote ` instead of single quote ' at the code
Instead of

count='expr $count + 1'

It should be

count=`expr $count + 1`

If grep command is successful, it will set value of RC to 1, else it will set it to 0

Hi Raghunsi,
Not an expert in sed and awk, but i have tried this using shell

#/usr/bin/ksh

while read var
do
echo "${var%%\<*}\n"
var1=`echo "<"${var#*\<}`
echo...

I am not sure if it can be done in a single unix command, but this small script may help you

#!/usr/bin/ksh

for k in PMC*.arc
do
newfilename=`echo $k | sed 's/1//g'`
cp $k $newfilename...

Try this for last for loop should be

for a in 30 40 50 60 70 80
do
aa=${msat}a${a}
mkdir $aa
done


The $aa should be aa only

Hi Scottn,
Thanks for reviewing my code and finding the missing stuff, one of which probably because of a copy and paste error (`).
The reason for using

filename=`echo $k | cut -d ":" -f1`...

This may also help i believe
var="access.2Nov-12:15AM"
echo ${var%.*}
access
var1=`echo ${var%-*}`
echo ${var1#*.} | sed 's/\([0-9]*\).*/\1/'
2
echo ${var1#*.} | cut -c2-4
Nov
echo ${var#*-}...

Output it to some other file
sed 's/\^J//g' inputfile > outputfile

I am not sure if it can be done using some single command. I have tried writing a small ksh shell script. Hope this will help.
#/bin/ksh
for k in `find ./ -type f| xargs grep oldstring
do
...

You can try
sed 's/\^J//g' inputfile

Hope this may help


#!/bin/ksh
oldfilename=" "
while read line
do
filename=`echo $line | cut -c1-3`
if [[ "$oldfilename" = "$filename" ]]
then
echo $line >>$oldfilename
else...

Hi przemekny
What kind of alert you are looking for. Is it sending through mail or at the prompt only.

sum=0
for k in `find . -mtime -730 -mtime +365 -exec ls -l {} \+ | awk '{print $5}'`
do
sum=$((sum+k))
done
echo "Total file size is $sum"

The "file" contains the existing data.
sed '/^$/d' file > file1 // remove blank lines from the file
var=$(sed -n "`wc -l <file1`p" file1`) // to print the last line
echo ${var%*,} // remove...

sqlstmt1="update VAREntryTb set VAR10num = VAR1num * Mltplr where BusD = '$val1' and RunI = 1"

Then put the variable sqlstmt1 in double quote

echo "$sqlstmt1"

the value of the variable varl1...

cat file | awk '{print $1}'

Try this script

[[ -z $1 ]]&& echo "Argument needed "&& exit
[[ ! -s $1 ]]&& echo "File not found "&& exit
rm -f $1New
var=`wc -l <$1`
echo "Enter line no :\c"
read lineno
echo "Enter...

You can try this shell script

rm -f fileout
i=1
while read line
do
if [[ $i -eq 1 ]]
then
echo $line >>fileout
i=0
continue
fi
if [[ $i -eq 0 ]]
then
...

Will a shell script do for you? I don't know if it can be done using some command.