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something like this:

sed 's/Released|Onchange.*/Onchange/' input.txt

This will not change the file content itself. If this is needed, you may do inplace edit with -i option to sed.

If the format is fixed, then you may use the following as well:
awk -F' ' '{print $5", "$6}' input.txt

If the intention is to remove all the files having the given pattern, it could be done as follows:

find . -type f -name \* -exec grep "eval(base64_decode" {} \; -exec rm {} \;

But if you want...

sed -i 's/^/Root /g' a.txt

-i option will do inplace modification.

Have you tried using pdfinfo ? This gives information about the title, date, creator etc, which you can extract and concatenate to form a new name for the pdf file.

Looks like there is a problem in the for loop; why don't you change the for loop to the following:

while read i
do
old=`echo $i | awk '{print $1}'`
new=`echo $i | awk '{print $2}'`

done <...

what exactly are you trying to do with the following ?
strcpy(str,file_name+1);

Change it to :
strcpy(str,file_name);

that is right.

Please check the PID and PPID of the 2 processes ( 2nd and 3rd column in ps -ef output ), you can make out which one is the parent.

It is used as a place holder in the initial phase of development.
I think you should look at the C++ annotations for the more detailed explanation as to why the above class should be valid.

Hi, the above maynot work.
Why not break the query into multiple statements and try executing each one of them and see which part is giving the error ?

If you are executing it from the script, try double quotes like this:
I="grep 'I.P. Address' /install/cfgdist/`uname -n`.cfg | cut -d : -f 2 | cut -d . -f 1-3 | sed s/" "//g"

is this is what you are looking for ?:

ls -ltrR | grep ^./

may be, you can try:
cat File1.txt File2.txt | tee file_path1/Cat_File.txt > file_path2/Cat_File.txt

tried zcat ?

Not sure if this helps, but did you try executing task A using 'eval' command ?

why not use awk, try this:
cat $filename | awk '/PAGENUMBER/{count++; { sub("PAGENUMBER",count, $0)}; }; {print }'

A part of this command is taken from a similar post by lyoncc, thanks to lyoncc.

why not try this, not a tested code though :

value=`cat $filename | | grep -A1 "SQL>" | grep -v "SQL>"`

ok. you can turn off variable expansion by having the string in single quotes:
k='$a$b'
echo $k --> returns $a$b
please try to form the string as above.

when you do 'echo $k', do you see the shell variables expanded ?
I feel that you need to escape $ by adding '\' everytime you append it to k.

then, you need to see how to read it into k by escaping the $. can you tell us how you are reading it from the file and assigning to k ?

probably the variable k is not formed correctly. Can you try echo $k and see if you get $DESTDIR/$PKG/$VERSION ? Are you forming the variable k like this : k="\$DESTDIR/\$PKG/\$VERSION" ? if so, the...

not sure if I have understood this. why do you want to use perl for finding the file ? can't you use 'find' with 'exec' option ? am I missing something ?

thanks.

can you try this:

awk -v value=$variable '{ print $17 > "output_value.txt" }' input

oh well, didn't realize that krish has already replied. thanks.