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Yes, it is. This is a problem given by my Operating Systems teacher a couple of weeks ago. It was a lesson on which he described the use of semaphores and an example that preceded this problem...

No, I'm afraid not. A process can wait on more than one semaphore, so we don't need that many of them. I am told it is even less than log(n) with base 2 (!), although I cannot prove it.

Hello, first of all I apologize if this thread is not in the correct section of this forum, but this one just seemed the most appropriate.
The question I have does not concern Unix specifically, it...