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Hi All,

Need a quick help on the similar issue...I am trying to replace the 87th column ina file with some other value but this command doesn't work for me.

awk...

Tried changing the name of the file, still zip is giving the error. Refer out put below.

current path is /export/home/jmirani/MAILExample/attach
count is 122
a001.jpg
a002.jpg
a003.jpg...

I am more than happy to try eval, unfortunately don't know what and where should i put this to get the result i am expecting.

I have read the help of eval command, but since eval doesn't zip the...

space in sed was my copy paste mistake.

I am also doinf echo before zipping and i am getting :
'First month of RIA 001.jpg' 'First month of RIA 002.jpg' 'First month of RIA 003.jpg' 'First month...

I have already arrange the files surrounded by quote, but for some reason it is giving error while zipping the files. I have also provided the results with the problem occuring.

Hi ,

I have written code which will ask the subject,body of the mail, attachment and mail id of the receipient.
Code will pick up 4 files zip it. It will zip all the files and then post the mail...

it worked properly

I have a file(old file) with names in it like
Jolly Mirani
Han Lee
stuart Lloyd

I want string to be added to these names . New file should look like
'jolly mirani'
'han lee'
'stuart lloyd'
...