Search Results

you can't mix both expect & ksh in same script. write two 2 scripts one reads the hostfile and sends instance,host, password to expect scripts. which does your job. here is the sample. this might not...

start()
{
su - $USER -c "${INSTALL_PATH}/bin/MyApp -X"
# or
# su - $USER -c "cd ${INSTALL_PATH}/bin/; ./MyApp -X"
return 0
}

1. print vtoc from source disk using prtvtoc -f filename
2. copy the above vtoc to new blank disk using edvtoc -f filename
3.above would create all slices /dev/rdsk/cxtxdxsx

copy slice by slice...

output shows on screen. if you want you can redirect them to some file. those extra slashes are for escape, other wise it wouldn't find that string as / has special meaning in unix.

were you able to run that script from terminal manually ?

find /files/accounting/ -name *.xls -exec grep -i '\\\\clttrut04\\dept' /dev/null {} \;

now you've correct script. you need to check smtp for mail sending/receving from that box. you may just check mails simply by sending mail from prompt. if you recive then we can look @ script...

There is syntax error in mailx command. use like this.


mailx -s "Subject of Mail " -c " CC List if you want to CC" xyz@xyz.com < "Body of the mail from file (or) out put of some command "

last_modified_dir=`ls -ltu | grep ^d | awk '{print $NF}' | sed -n 1p`
files_to_be_moved_to=`ls -ltu | grep ^d | awk '{print $NF}' | sed -n 2p`

tail -r <filename>

would reverse entire file.

This /usr/sbin/for has this problem. You can fix this using /usr/xpg4/bin/for or

while read line < cat filename
do
echo $line
done

this would print entire line. but if you use for it would...

Use this to get size directory wise recursively

find . -type d | xargs du -sk

just execute manually..not through script and give a try..

find . -type d -size +<size>c -ls

Hmm..it works fine for me..that's right command..

Thanks Jacoden...nice docs there...

This doesn't look like cron issue..may be sql is exiting. so the cron is catching that error...look for sql..if possible put spool on that sql..

#! /usr/bin/sh

counter=1
for i in `cat movies.txt
do
mv $i `dirname $i`/${counter}_`basename $i`
counter=`expr counter + 1`
done

Give a try with this if doesn't work..paste the log here :)

Dude!!! I don't think I understood your problem fully..but here is what i tried...take a look..


t1=`echo "$line" | awk -F"," '{print $1}'`
sumt1= `echo "$line" | awk -F"," '{print $3}'`
...

if you can get the config file like this..you may use below script.

config file format is like this
########################
config.cfg
servername =
filepath =


#student attributes...

Hmmm..looks strange to me..anyways give me output of this..

#!/bin/bash
Keepdate=`/bin/ls -ult --full-time| sed 1d | head -1 | awk '{ print $6 }' | awk -F"-" '{print $1}'`-

echo $Keepdate
...

cron is running as root or other user id ? login with same id and try to run manually. let's c that works or not..can you paste the error again & if possible contents of sql u r running...

#! /usr/bin/sh

counter=1
for i in `cat movies.txt
do
mv $i ${counter}_$i
counter=`expr counter + 1`
done

paste your text file here and the out put you want..so accordingly we can write the command. :)

it won't delete becuase i commented out rm. try this..btw..what is the unix version do u use ?

#!/bin/bash
Keepdate=`/bin/ls -ult --full-time| sed 1d | head -1 | awk '{ print $6 }'`

echo...

give me out put of this..

#!/bin/bash
Keepdate=`/bin/ls -ult --full-time| sed 1d | head -1 | awk '{ print $6 }'`

echo $Keepdate

#/bin/ls -ltr | grep -v "$Keepdate" | awk '{print $NF}' |...