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awk '{printf "%s ",$5} ' file* | tr ' ' '\n' | while read a; do read b; echo "$a $b"; done

Good starting point

stat --printf "Human Readable: %A \nGroup name of owner %G \n" file

No paste needed.

if you want the columns side by side you can do
awk '{printf "%s\t",$0} END '{print}'' file*

Be very careful when you run this.

First identify what the directories are:

find / -name "??????????" -type d -empty -ls


Then delete (be careful, I am warning you)

find / -name...

IMO, its really a bad idea to parse HTML files using SED/AWK

Your best bet is to use PERL,

HTML::TreeBuilder - Parser that builds a HTML syntax tree - search.cpan.org...

This is not a command. Its probally in your /etc/sudoers file.

Sudoers Manual (http://www.gratisoft.us/sudo/man/sudoers.html#examples)

Define "system directories". Also, doing a find of "/" will take a very long time and you may not have permissions depending on your access.

You may wait to use

-fstype ext3

to avoid...

for starters its not a good idea to parse your ps output.

Try using ps -eo pid

run it on a faster box?

What exactly is the script doing?

awk '{if (NF==3) { printf "|%s\t|%s\t|%s|\n",$1,$2,$3}}' file

not tested but I would would

awk '{print $5}' file* >> result.txt


What is the "desired" format?

Please be more specific. Your example makes no sense

awk 'BEGIN {m=0} {a[NR]=$0;if (m<length($0)){ m=length($0)}} END { for (x in a) { if (length(a[x])<m) { for (i=length(a[x]);i<m;i++) { printf "0" } } print a[x] }} ' file

To compare folders I recommend you use rsync

rsync -n -avxl src/ tgt/

This will show you how src differers from tgt
Is this what you are looking for?

Here is mine, ugly but should do the trick

(not tested)


awk 'BEGIN{i=0}
{ content[NR]=$0; if (($0=="")) {b[i]=NR;i++} j++;}
END
{
for (x=0;x<=b[0];x++)
{print content[x] >...

something like this, maybe?

awk '{print "mkdir "$1}' file | sh

paste a sample output for your question....

Something like this?

filename a.awk

BEGIN {
RS=""
}
{
for (i=1;i<=NF;i++)
{
array[i]=$i
}
}
END {
for (k=1;k<=i-1;k++)
{
...

Something like this, maybe?
Filename:blk.awk

BEGIN {
RS=""
}
{
for(i=1; i <= NF; i++)
{
array[i]=$i
}

...