Search Results

You guys are awesome !!!

Thanks for your reply. I understand you are trying to put the date part in first column in list output. But then how do you select the correct file? My requirement is to somehow pass '20060803' and...

Hi

I have a directory having following three set of files as follows:

test.20060804
test.20060801
test.20060802

I want to list the latest file which is less than 20060803. in this case, it...

Well

Not everybody is comfortable with awk or nawk..Anyways, just wanted to give an alternative (may be not simpler for awk/nawk gurus) way to accomplish the task.

Did not hurt anyone, did it?

Hi

Don't want to beat a dead horse but following could be an alternative and i believe much simpler solution

while read name
do
name=`echo $name|awk -F":" '{print $1}'`...

Jim

Once again, thanks for your script. I tested it out and found out that there is a upper limit of 25. Contrary to what I thought, it looks like 25 is not the limit of "wait" but apparantly it...

Jim

Thanks for your reply

Per your code, does "wait" wait for all the bg jobs? I had heard there was some kind of upper limit.

Thanks

Hi
I have the following piece of code that is calling another child process archive.ksh in the background

while read file;
do
file_name=`ls $file`;
ksh archive.ksh $file_name &;
...

Thanks for your reply

You were right

/opt/cdedev/informatica/InfSrv/app is a symbolic link to vikas/cdeddev/app.

I did not know that you could create soft links for directories as well....

Hi All

I Know it is a really basic and stupid question perhaps...But I am going bonkers..

I have following valid paths in my unix system:

1. /opt/cdedev/informatica/InfSrv/app/bin
2....

Hi
Thanks for your reply. I had edited the post to include a fouth line of code? Could you plelase help me understand that as well?
TIA
Vikas.

Hi All,

I am trying to understand and change some code written by some programmer a while ago. There are following three lines of code that I am unable to grasp. Could anybody please help me...

Thanks Jim and all

I guess I got my answer. Jim put it down nicely by saying 'you dont use "or" in commands like that'

Thanks all for your replies...

This got very interesting actually. I was quite surprised to see that sed considered '|' as literal '|' and not any operator.

In that case, why it did not consider '[ ]' literally in my earlier...

Matrixmadhan

I dont think that would be a very clean way to do it.. I mean if there is something like '|' that is allowed in regular expression and if it is supposed to work with sed, it should,...

:confused: Thanks for your reply and i guess I am still confused. By using a '|', i meant to imply an 'or' to sed. I was telling it to convert either .gz. or .gZ. or .GZ. or .Gz. to a dot

It...

I think I lost you there when you said, there is no pattern. I tried the folllowing code for a compressed file and it works:

filename.z.timestamp
filename.Z.timestamp

echo $filename|sed...

Hi

I started the thread with the example. To make it clearer, below is the real life example :

I receive a file with a timestamp appended to it from source system. If it is a compressed file...

Thanks Vino. It worked for me. Is it right to assume that the regular expression '|' does not work with sed and probably it is just meant to work with awk or grep?

Anyways, thanks again. It worked...

Thanks for ur reply. However, i am still interested to know whether it is possible thru sed or not. The reason is, if it contains anything else than a .txt or .csv, i dont want to convert it into...

Hi

I am trying to replace an extension in a file name using sed as follows:

echo $filename | sed 's/.txt/.doc/'

My objective is to replace any extension with let's say a .doc extension....

Hi Glenn
Thanks for your reply. However, $4 can definitly be calculated at the runtime. As I said i ran this piece of code on some other unix box and it ran fine. Also if i use nawk, it runs fine on...

Guys

I finally resolved the problem. As i mentioned in my last post that somehow, this code was working on one box and giving prob on second one. Well, i try the same code with "nawk" on second...

Guyz,
Plz ignore my post. I just tried it on a different unix box and it worked. Both are korn shells. I have no idea why it did not work on the first one. I am going to do some further R&D on this....

I guess by mistake i submitted this twice. Plz ignore this one.
Thanks