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Thanx Guys!

I was using CygWin, I guess its not a good idea to test everything there.

Anyways I came up with something what "oombera" has mentioned.

its like:

ls -ld | awk 'length($9)>=5...

nah, it doesn't work, thanx for the try though...


:-)

Hi there,

Could some body tell me a simple way to get the following output.
The list of directories having atleast five characters.

I know the simplest way is:

ls -ad ?????

but that from...