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thank you very much for answering and helping me!




that's right, the problem comes from the variable PS1.




in fact when i use the csh shell instead of bash my problem disappears.

...

yes, that's right, if i just write:

printf("test\n");

then it appears properly on screen.
but what if i don't want to use \n ?
and also, the new bash line should appear _next to_ my data, but...

hi everybody,
when i run and compile this:

printf("test"); fflush(stdout);

nothing appears on screen.
if i try this:
___________________________________

printf("test"); fflush(stdout);...

:D

that's great, you were right!

nice guess. now i finally understand what's happening, thank you!

:cool:
anyway im disapointed with this bash shell...
is there a way to set the bash so...

hello everybody,
here is my problem:
________________________________________
#include <stdio.h>

int main()
{
int i=10;
printf("value is %i",i);
return 0;
}...