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Time service as suggested, or if not available maybe running date +%s if your date command on each supports it. That will give seconds since the epoch and you can just do integer compares.

If you...

Understood. What I was indicating was that if the subdirectory foo/x.mak exists it will be matched if ./x.mak is used where if \./x.mak is used it will not.

I guess actually both dots in the...

A couple of things...

First, you should escape the dot in your pattern so that something like y/x.mak doesn't also match. It might not be a probability in your current directory structure, but...

Completely hard coded, but this will work"


awk '/"lan3"/' file

That didn't work because you don't need the word signal, just pkill -2 inetd


#!/usr/bin/env ksh
# should work with bash too
# usage: scriptname [-][signal-number|signal-name] pattern

if [[...

Yes, the "DISPLAY" command should execute and pipe it's output to grep. It would help if you could post the whole script, or at least the portions that include the assignment to the DISPLAY variable....

Do the records from your log file have a timestamp? If not, it's going to be difficult at best. Would be best to post a sample of the log file with any sensitive information X'd out.

The scripts posted earlier in the thread work on the original data as input, not what you are giving it. Did you try with the original data? I ran the original data through the two I posted and the...

Have you tried reading the data into an array which would allow you to avoid the substring overhead which I believe is costing you. Your original code ran in about 4 seconds for me using Bash and...

ERK!!

I made a change, and tested it, but failed to see all zeros. Going blind I think.

I've fixed the bug by reverting to my original logic and it works now for me. THANKS!


awk '
...

Have a go with either of the programmes below. If your input file is huge, you may run into issues because these load everything into memory. There are ways to work round those issues, but have a...

Assuming your data is in a file named t.data this is one way:


awk '
/>/ { split( $1, a, ">" ); sect=a[1]; next; }

/Start/ {
s = "";
printf( "%s ", sect );

...

I tried in Kshell -- it needed $(( ... )) and assumed that bash required the same. My bad for not testing with bash.

Thanks.

Even with a #! change, I think something like this is needed:


${infile:0:$((len-4))}


as long as bin/sh is a bash or kshell.

You can download it and build it in your home directory -- no need to 'install' it. Of course, company policy might prohibit that too which is too bad.

Ah, very good, thanks.

Have a go with this:

awk '
/property name=/ {
gsub( ".*value=" Q, "" );
gsub( Q ".*", "" );
print;
}
' Q="'" RS="[<>]"

...

How were you testing it? if you were using echo to echo it and pipe it into awk, were you using double quotes round the whole string? That won't work. Use single quotes:


echo '<property...

If you're using a gnu-like awk that supports a record separator pattern, this might work for you:


awk '
/property name=/ {
gsub( ".*value=\"", "" );
gsub( "\".*", "" );
...

If you write your scripts in Kshell, you can use shcomp which will convert the script into a binary representation that Kshell can execute. You then put the executable file out in a public...

Try:


sed 's/ //' input-file >output-file

First of all, you don't need to cat into a while, you can redirect the file into the while:


while read stuff
do
echo $stuff
done <$ELOG


Further, the use of awk isn't needed either....

If you have a modern Korn shell installed, ${.sh.file} should contain the name of the file that was sourced.

Have a try with something like this:

#!/usr/bin/env ksh
echo "Running test2.sh...

Pipe it through sort.


awk '
{ a[$1+0] = $0; }
END {
for( x in a )
{
printf( "%s", a[x] );
sc = " ";
for( i = x-10; i <= x + 10;...

Assuming no duplicate field 1 values, and that all will fit in memory this should work:


awk '
{ a[$1+0] = $0; }
END {
for( x in a )
{
printf( "%s", a[x]...

Have a go with this:


awk '
{
split( $1, a, ":" );
sum[a[1]] += $NF;
}
END {
for( s in sum )
print s, sum[s];
}
' input-file

...