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hi

I have a line as given below. I need to match "COLUMN_NAME" and get the every third value ie words in between quotes completely (' ')


Sample Input -
COLUMN_NAME Like '%value%' Or...

It gives the below error

date: illegal option -- -
Usage: date [-u] [+Field Descriptors]
date.sh[14]: test: argument expected


My env is pure ksh, I doubt that about bash executing here.

Yes, I need to generate a list of year-month pairs between two dates.

I need to generate a file which should have range of year and month in the below mentioned format:


200901
200902
.
.
.
till
201311


This jobs runs on-demand. Even if this is ran...

Thanks krishmaths and that was working as expected...!
Learned how to declare variable in "awk".

Thanks..thats working..!

But when I tried passing runtime value for column count its not working

awk -F"," '{if(NF<$ColumnCnt) {print "Line number : "NR" has less number of columns which is...

I have a data file (which has five columns) from which im finding column count of all the records and writing into separate file say "colcnt.txt". And I find one (or more) records have less column...

Hi,
I need to find the field separator for the given files.


Ex-
abc.txt is "|" delimited file , when I give command the output should be "|" and that shud store it in another variable.

...

Sorry, its a sensitive dat. A '$' symbol is getting appended at the end of each line.

It is working with .txt files but not with .csv files

I have a csv file "file.csv" which has 5 records but when I check record count for file.csv in unix it shows as 6, the last line is empty and I need to omit and need for processing.
Kindly help.
...

ls -e not working

Im using AIX.

I need to get the current year for the files that has been created today.
Ex-

when i list in unix console it shows

ls -l abc.txt
-rw-rw-r-- 1 user1 user1 33 May 2 08:58 abc.txt
...

Yeah Its working I thought of getting it in single command rather than executing it 5 times.


for i in {1..5}
do
cp details.csv details{$i}.csv
done

this is not creating 5 different files...

I need to create a copy of details.csv with different names (details1.csv,details2.csv,details3.csv,details4.csv,details5.csv) along with the data. The data must be same in all the files but only the...

I have a file details.csv and I need to create 5 files in same folder named as details1.csv,details2.csv,details3.csv,details4.csv,details5.csv along with contents of details.csv

Thanks in...

sorry I just gone out of mind :confused:
that was a different topic and I posted it wrongly, thanks for your concern and you have helped me in framing out the code. :):b:

just one more help...

I have 2 data files and 2 crtl files.
Say-
A.txt B.txt
C.crtl D.crtl
crtl file has filename|processdate|recordcount
the data in crtl files must be compared with all the txt files
and it...

If I pass 3 three arguments( run time) , it should take $1 and $2 and compare and should print the result as per below code
and in next run it should take $1 and $3 and do the same process and...

the scenario is -
If I pass 3 three arguments( run time) , it should list all .txt files from a path to temp file
if I pass 2 arguments ( run time) , it should list all .csv files from the same...

while I pass 3 arguments

/path crtl1 crtl2

to a shell script will the console takes 2 crtl files in order ? Dont we need to specify to terminal that it should process 2 process or it takes...

I think you took it in other way, I wont check for the presence of crtl files in the path that I am passing as an argument.
I match the contents of crtl files (filename|date|count) with that of...

To the below i pass "path" and "crtlfilename" this code works for one crtl file what if the path contains 2 crtl files?? what changes needs to be done ??
first time it shud take path and crtl1 file...

I am passing 3 runtime arguments to a shell script

$path crtl1 crtl2


the crtl files contains data(filename|date|count)


filename.txt|02/05/2010|10


The path contains the original...

I have tried all possible but the console doesnt goes into the while loop itself only if it goes it will check for file existence and it prints relevant message.
I m not sure whether I have missed...