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if you are using dos shell jsut double quotes the file name like "you'are crazy.mp3"

If you are using windows dos shell you jsut need to specify the file it in the double quotes "you're cray"

Fantastic , that was new to be , I thought of getting rid of the the "disk write" happening while out putting it in to a file.

sed -n "$begin, $end" $logfile >engines
exec < engines
while read...

You mean I ahve to change the below line
sed "$begin, $end" $logfile | while read line

to
exec < test.file
while read line

But I do not want to read file fully , but only from begin to end.

I am readinga file lin by line and based craeting a arry of unique elemenst from the second column of the line. However when i coem out of the while loop my array becomes empty , can eny one tell me...

Thank you!

I need to read a file fron nth to n+m line by line using bash

ie
while read line
do
# soem stuff
done <<file

But The file is so big I am only intersted in reading ceratin portion of the...

Thansk , But I also have to print the originla values , with diffeences 0, incase I did not find a matching line.

I got it, it look like bash does not support floating point arithmetics

I have to use awk, like the following

diff=`echo $f1col1 $f2col2 | awk '{print $1-$2}'

I have a two files
>cat file1
jjjjj 10.345 6.673
ppp 9.000 5.883

>cat file2
mmm 80 10
jjjjj 10.305 6.873
ppp 9.000 5.883

I am reading file 1 line by...

fanstastic it worked ! My file is very large , so I do not want to grep it again and again! Instead do s single grep and store all insatnces together
Thanks

I have the results of a grep with -n store in a shell variable
ie
VAR=`grep -n -e 'PATTERN' file`
How ever I am missing the line breaks in the variable , How do I store the resualts of grep with...