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again, thank you very much sir :D

Can i have more question to this issue please?

i modified your script to this:
/usr/xpg4/bin/awk -F':' '$3>100&&$1!~/nobody/||$3==0{gsub("\\..*|/.*/","",FILENAME);print FILENAME";"$0}' *.pass >...

works like a charm thanks

thank you but:
awk: syntax error near line 1
awk: illegal statement near line 1
:(

Hello guys,
please help me to make simple script for parsing passwd file.
I have many passwd files from our servers, named server1.pass, server2.pass etc..
so
for server in `ls *.pass`
i need...