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my solution (i added a for loop to print the output text everytime the script is run, you can remove it if you don't need it.)

#!/usr/bin/python

import urllib.error, urllib.parse,...

does this do what you want?

#!/usr/bin/python
import math

f = open('exams.txt','r')
total = []

while True :
try:
l = f.readline().split(None,10)
L =...

python

container = open('your_file_here').readlines() # load file info into variable container
container = [item[:3] for item in container] # remove trailing spaces or newlines
for item in...

to print the value of a set variable just use the variable name, no need to add the "$"

{print v

:b: i love these oneliners

what exactly are you looking for? to know which ones items match, or which ones don't?

look up awk and setting the delimiter (FS)

while read line; do
current=$(echo $line | awk '{print $1}')
[ "$current" != "$check" ] && echo ""
echo $line
check=$current
done < your_file

so you want to exit if there are any errors?

see if what i wrote works, it will directly pipe STDERR to exit 1, so any errors that pop up should trigger it immediately

#fd 6 has the same target as STDOUT
exec 6>&1
#STDERR is redirected to fd 1 (which means any errors go straight through to the pipe and trigger exit 1). if there are no errors, STDOUT is...

:b::b::b:

echo "(PROC_PROC_ID == 12183)" | sed 's/\(PROC_PROC_ID ==\).*/\1 whatever you want here)/g'


mo@mo-laptop:~/scripts$ echo "(PROC_PROC_ID == 12183)" | sed 's/\(PROC_PROC_ID ==\).*/\1 whatever you...

this gets my vote. i must've been in zombie land when i used ${#line} (not enough coffee...)

i've also recoded the other piece of code to this, you can use whichever you prefer...

read pattern...

AFAIK, awk will not accept variables that need to be expanded, which means that any pattern matching you want to do will have to be hard coded.

this solution doesn't use awk, giving you more...

you can also use grep's exit status $? to check if there is a pattern or not. if there is a pattern exit value is 0, otherwise 1.

mo@mo-laptop:~$ ls | grep scripts
scripts
mo@mo-laptop:~$ echo...

#!/bin/bash

for line in $(cat file2); do

echo $line | awk 'BEGIN { FS=";" ; OFS=";" } { print $1, $2, $3 }' >> file3

done

lin=1
for line in $(cat file1); do

pat="$(sed...

check the man pages for sort. then once the data is sorted use sed to print out the first and last item.

here's an example using ls, i'll sort files by size then print the largest

...

page 102, bash beginner's guide, tldp.org

tsk tsk i didn't read the problem :rolleyes:

sed doesn't work for you?

sed 's/;/|/g' file

hey scrutinizer.

yeah i just figured it out. basically it takes input from the previous pipe, right?

awk should work as well:

print "$isResult" | awk '{ print $1 $2 }' >> test.txt

bash:
#!/bin/bash

file=/home/mo/scripts/group.txt

for line in $(cat $file); do
if [[ $line == [0-9]* ]]; then
symbol=$line
else
echo "$line...

what's the pattern of the file? do you want to retain whatever comes after the numbers? will there always be numbers?

assuming there are always numbers in the output and you want to retain...

haha i was about to say the exact same thing. it's been ages since i last saw a goto statement