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I see a possible problem.
The asterisk symbols on input might be evaluated in awk as an expression.



cat testInput | awk -F' ' '{printf(" %s",$2)}'
8-17,113

See how two ones' (11) came...

Edit: fixed some trivial typos

for X in `i=0;while ((i < 300)) ; do echo $i ; ((i += 1)) ; done`
do # the for loop cmd list
printf "for X:%3d\n" $X
done

Some shell parameter substitution might help.

blar=foo.JPG
echo ${blar/JPG/jpg}

will output:
foo.jpg
So that means you can do:

for JPG in `find /path -type f -name \*.JPG` ; do mv $JPG...

No person is wrong.

Scottn's solution is, in my personal opinion, not as ideal as my own proposal.

The reason is that Scottn's solution requires to invoke `ls -l`, where mine uses pure shell...

for FILE in a*
do
ls -l $FILE
strings $FILE
. . .
done

cat /path-of-dir/*.sql | sqlplus "uname/password@sid"