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Thanks Ravinder for the explanation!
And thanks for the heads up, MadeInGermany.

If my input file contains multiple fields (14), would there be any way of doing this for every even numbered field...

Hi Ravinder,

The code works great!

What does the "1" at the end of the code do?

Thanks,
Rabu

Hello, I have the following input file:
1 3 3 2
3 3 4 0
4 0 5 4
5 2 2 0
5 3 4 0
6 0 3 2

I am trying to remove all zeroes in fields 2 and 4 and replace them with "1's"

I tried the...

Hi Don and Scott,

I apologize for not clearly stating the problem, but say my actual input file contained 14 fields, and I only wanted to print all fields except for 6 and 7. Wouldn't a for loop...

Hello,
I have the following input file:

A=1;B=2;C=3;D=4
A=4;B=6;C=7;D=9

I wish to have the following output

1 2 3 4
4 6 7 9

Can awk split be used to do this?

I have done this...

Hi,
What I meant was that my actual file has the same format, but is much larger. It contains many more fields. I just put in three for the sake of simplicity.

There should be no space at the...

Hello,
I have an input file that looks like so:

1 2 3
4 5 6
7 8 9

and I just want to print the first and third column (note: my actual file contains many many more fields so I don't want to...

Hello, I have an input file that looks like so:
LDLR
LDLRAD4
VLDLR

when I grep "LDLR" I get an output of:

LDLR
LDLRAD4
VLDLR

Since all names have "LDLR" included within them, but all I...

Hello, I have the following dataset

1
1
2
2
2
3
3
4


I want to keep just one instance of each number seen:

1
2
3
4

Hello, I have the following input data:

A C
AA GG
A G
CG AG

the code I tried:
awk -F" " '{ if ((length($1==1) && (length($2==1))) input_file

is not working, I need the output to be (such...

Hello I have a very simple input file in which there are a list of numbers:

1
2
3
4
5
6
7
8
9
10

My actual dataset is about 200 lines long. I was wondering how to add different...

Hello everyone, I have a dataset that looks like:

1 2
3 4
5 6

I was wondering if was possible to divide values within rows:
1/2
3/4
5/6

I don't think using awk -F"\t" '{ print $1/$2 }'...

Hello everyone, I have a dataset that looks something like:

1 3
2 2
3 4,5
4 3:9
5 5,9
6 5:6

I need to remove the rows that contain a comma in the second column and I'm not sure how to go...