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The output i get is this.
> findlog.sh 05/05/09
Invalid date format

Is this valid..

if [ $mydate = @(0[1-9]|1[0-2])/@(0[1-9]|[12][0-9]|3[01])/[0-9][0-9] ]; then
exit 0
else
echo "Invalid date format"
exit 0
fi

Thanks all. I appreciate your help.

hi,

just want to validate date input in an argument if correct with the format mm/dd/yy. no need to check if input date is within range or not. what i need is to check only if it is on 'mm/dd/yy'...

Hi..

I'm a newbie in KSH. Need help. How can I validate input date format in argument using format mm/dd/yy. Eg. > findlog.sh 12/30/09. Any info/help is highly appreciated.

Thank you all. Its working now using -s option.

Just want to ask if the below code is correct;

if [ {cat out.txt |wc -l} -eq 0 ]; then
echo "No log found from " $data
exit 0
else
cat out.txt
fi

this is to test if the content of...

ei..its working great! thank you so much.

The 1 or 2 digits is ok but when the 3 digit is used which is the correct argument, it is showing wrong number. eg 035 should also result in 035. Thank you.

I tried to test the below code but it is showing me odd results

data=`printf "%03d" $1`
echo $data

Sample test:
> findlog.sh 001
001
> findlog.sh 020
016
> findlog.sh 035
029
>...

Sorry..'find' is just a sample, the actual name is 'findlog'.
Is printf works in ksh? I'm just a newbie. Thank you.

I want to check the argument in KSH. If the user type in the prompt 'find 3' it will format 3 to 003 to match the data in the text file. Same as with 10 to 010. Always begins with 0.

eg.
...