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Anybody think root can do all, no.
This message sed that exist job started as root.
Root can't do it. Job ended with exit "1".

you need package
mysql-libs-5.1.47-3.el6

I don't known.
Don't worry.
You known what scipt start about 14:30.
check this script, if it is safe try do the scipt as root....

.............................................

echo " Searching for the search String from "${archFilePattern}" "

string is collect of charakters, can be only one character
OK?
can do:
tr -d '\015\080' file
or
tr -d 'acd' file
I think, your shall sey you what use "" or ''.

It's only one filesystem?
let:
df -k; df -i;quota

I think, you start vi in xterm?

xterm
OK?
at xterm
vi filename

awk '{ i=1;while (i <= NF) {print $i, $(++i), $(++i); ++i}}'
shorter:
awk '{ i=0; while (i < NF) {print $(++i), $(++i), $(++i)}}'

Dear hindesite!!
For me, your comment about my chance is unnecessary.
You work though you 'not good at sed yet'.
I recall you, 'grep' you written.
What for do I know that you don't want the name...

try

include(`bash_macros.m4')
START_SCRIPT(`fake_script',`Automation Dept.')dnl
GLOBALS()
SANITY_CHECKS()
FUNCTIONS()
MAIN()
END_SCRIPT()

exactly:
grep "^r [^ ]* 3 "

Is it good?
awk 'BEGIN{FS="`";RS="|";OFS="`";ORS="|"}{print $1,$2,$3,$4|"tidy -config tidy.cfg";print $5|"tidy -config tidy.cfg"; print $6,$7}' infile.csv > outfile.csv

set nohls
forever
vi .vimrc
add line:
set nohls

change awk to gawk
your awk don't like pipe

to test try
echo "a"| awk '{ print $0 | "cat 1>&2" }'

mount the filesytem
test, have you any snapshots:
mmlssnapshots /dev/gpfslv -d
example:
Snapshots in file system fs1: [data and metadata in KB]
Directory SnapId Status Created ...

Now,it's new homework?

stty
set the options for a terminal, at cron you haven't terminal
you can't use the command

My propossition, change job;
SHELL=/usr/bin/ksh; export SHELL; . $HOME/.profile 2>/dev/null ; xxx.sh...

It works too:
sed -n '/ORGANISM/{n;N;N;N;s/\n/ /gp}'
readable format:
sed -n '/ORGANISM/ {
n;N;N;N
s/\n/ /gp ...

grep $varEQ *.ini | sed -n 's/\(.*\)#.*/\1/p' >> /tmp/ini_FTP_settings_$INTFC.lst

sed -n '/ORGANISM/{n;p;n;p;n;p;n;p}'|tr -d '\n' && echo
OR(can be not work)
sed -n '/ORGANIZM/{n;p;n;p;n;p;n;p}'| sed -n 's/\n//gp'

define(`START_SCRIPT',`#!/bin/bash
#####################################
# File: $1
# Auth: $2
# Desc:
#
# TODO:
# BUGS:
# RCS: $Id$
#####################################
')dnl ...

I used "z" as "/" in s command s/REGEXP/REPLACEMENT/FLAGS

thanks scotnn. thanks.
echo "/a/bc/def/PAT_logs/g/hi/jkl/" | sed "sz/PAT_logszzg'
it's better:
echo "/a/bc/def/PAT_logs/g/hi/jkl/" | sed "sz/PAT_logszz'
output:
/a/bc/def/g/hi/jkl

pwd | sed 's/\\PAT_logs//'

pwd | sed 's/\\PAT_logs//'