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% character is understood in a different way by cron so we had to place \ before %

I tried this it and it worked, should work now


#testing
03 14 * * * [ "$(date '+\%a')" = "\Thu" ] && /path/to/script > /tmp/
test101.log

00 6 1-7 * Sun [ "$(date '+%a')" == "Sun" ] && /path/to/myscript.sh

---------- Post updated at 11:14 AM ---------- Previous update was at 11:08 AM ----------

try this hopefully this works
...

No luck
$ find . -type f -name '*sas7b*' | nawk -F/ 'NF-- && $1=$1' OFS=/ | sort -u
./employee.sas7bdat
./employee.sas7bndx
./employee1.sas7bdat
./sasuser.v91/regstry.sas7bitm...

posix,

Thanks for the providing the command. Want I really want is shell script outputing just the directories and subdirectories and not list the files.
$ find . -type f -name '*sas7b*'...

I'm looking for a script which outputs the list of directories and sub directories from root level consisting of specific files. For instance I want shell script to list all the directories and...