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No, you don't have it correctly. There are a couple problems with your line:
1. convert takes 2 filenames:
convert <inputfile> <outputfile>
If you want to perform the operation on the same file,...

Tricky part is that commas may be present within the field (that's why the quotes)
Yoda's solution will not work for files that have more than 6 columns, or files that have commas in the last two...

You missed the type:

find /local/home/app/cases -iname '*\.sh' -type f -exec chmod -c 744 {} \;
Escaping the period is not really necessary, and if there is a lot of files, using xargs is more...

Fantastic!
Thank you guys for pointing me in the right direction!

Hi,
I am writing a C++ application; in which at one point I fork() a new process, which executes a shell script (via execv() call).
Now the shell script can take a while to finish (tarring, burning...

Hi all,
I am writing a mount/umount procedure for CD rom and getting into the problem that /etc/mtab is not in sync with /proc/mounts.
Then I am ending up with a bunch of dangling /etc/mtab entries...

From man ssh :

Better yet, change IFS only locally, for this while loop. And you can avoid the cutting if you just throw in another dummy variable:

while IFS='|' read first second rest ; do
echo $second ...

1,$ line range; apply the following command on all lines ('$' in this context means last line). This part can be omitted since the full range is default.
s/foo/bar/g substitute (s) 'foo'...

Or
awk '{for(i=1;i<=NF;i++) $i=$i" "$i+1" "$i-1}1' numbers.txt

I agree that awk solution is more readable, but just for the heck of it, here is sed command that should do the trick:
sed 's/.*\("[^"]*"\).*/\1/'

Like this?
awk '/^[^>]/ && length($0)<10{print hdr"\n"$0}{hdr=$0}' input

May I ask what do you expect from testing against the same condition twice?


Try:
awk -F- '/FAILURE/{if(!seen[$5,$6]){cnt[$5]++; seen[$5,$6]++; } if(cnt[$5]>10) print $5,$6}' logfileNote that...

Try
egrep -m1 '/user/data/[0-9]{7}/'

find /mahe -mmin -30 -ls

less than 30 minutes ago: -mmin -30
It's all in the manual: man find

You can use -mtime of find(1). -mtime -1 would list files newer than 24 hours. Alternatively, you can make a timestamp every midnight (from cron), and check with -nt, if your shell's test...

Perl and sed are not the same thing. Although I am quite rusty in Perl, this should do the trick:
perl -pe s'/([][])/\\$1/g'

Try this:
awk '
{a[$1,$2]=$3; b[$1];}
END{
for(i in b) #print header
printf("\t%s",i);
printf("\n");
for(i in b) { #each row
printf("%s\t",i);
for(j in b) #each...

awk -F"[=,]" '{prev=$4; print; getline; print $0","($4-prev)/($4<0?-$4:$4)*100"%"}' input

The highlighted part basically does an absolute value of $4.
Note that you'll get into problems if the...

You can split on either = or , and hard-code 4th column:

awk -F"[=,]" '{prev=$4; print; getline; print $0","($4-prev)/$4*100"%"}' input

Or:
cat inputfile | tr '\n' ' ' | sed 's/ CAR /\nCAR /g; s/ $/\n/'

Try this:
awk -F= '{prev=$NF; print; getline; print $0","($NF-prev)/$NF*100"%"}' input

Yes, it would, absolutely.

What system are you on? What awk are you using?
If on Solaris, use nawk instead.