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After getting number of rows in one file, you can use sed to split it

sed '$begin_from,$last_to w new_file1' original_file

as begin_from and last_to are your start and end lines, "w" means...

If you get number of files to be installed, you can use the following as a starting point

count=0
while [ $count -le 10 ]; do
count=`expr $count + 1`
sleep 1
echo -n =
done...

I can't understand what really you want, but to extract the password , you can use

cut -f 2 -d =
-or-
awk -F = '{print $2}'

danmero, can you explain your code please
what "%" means here??
thanks in advance

tar -xvf /dev/rmt0 .
You can replace the " . " with the destination where you want to restore the files.

You can use a script like this

cd /your/core/file/location
if [ -e *.core ]; then
num=`ls *.core|wc -l`
mail -s "Attention" name@yourmail <<message
you have $num .corn files...

Try this

x=example.tar.z
y=`echo $x |cut -f 1 -d . `
echo $y

To backup all of your disk to a tape for example
go to disk root, then

tar -cvf /dev/rmt0 .

I got the answer of my and balamv question, "not_using_0" was assigned to dirs in the first position, and the index was began from the position 1, so it is no matter what is the first element, as we...

mschwage, It works Great
But I can't unerstand why u gave the value of "not_using_0 to dirs, as balamv asked ??
balamv,about the for statement, it test all items in the current directory if it is...

Try this

for file in php1 php2 php3 ...
do
sed -e '$d' $file > $file.tmp
rm $file
mv $file.tmp $file
done


Replace php1 php2 php3 ... wth your files

if u can get the row number, u can use "sed" as following
sed -e '1,301d' -e '364,$d' mylog >log_result

as it delete from row number 1 to numer 301 , and from 364 to the end of ur log, then write...