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Not the best solution I'm sure ...

curl -s http://www.tidetimes.org.uk/southampton-tide-times.rss | grep description | sed -n "s/.*\([0-9][0-9]:[0-9][0-9]\)/\1/;s/\([0-9][0-9]:[0-9][0-9]\).*$/\1/p"

To get each line separately you need to 'read' each line from the variable

for dir in "`find ./ -type d`";do
echo "$dir" | while read line; do
echo "Found: $line ,yeah!"
done
done

Here is a quick solution


#!/bin/ksh
#set -vx
# # set counter for detecting the script
typeset -i script_count=0

# # set loop count for 24 hours, change as needed
typeset -i...

Maybe this is what your looking for...

grep "^[&?s]*ession.id=[a-f0-9]*" file

Each time you run your backup use 'touch' to create a file called backup_complete.txt, then the next time you go to backup you can use find to backup all the updated and new files.

find . -newer...

Here is a quick solution to get the line with the file and completion time.

sed -n '/^\//N;s/\n.*$/ /p;/^Process /s/^.* \([0-9]\)/\1/p' file

I'm with kshji the script most likely has an unmatched quoted pair. The easy way to find this is to download an editor that understands shell script. I use 'jedit' on my pc and copy any scripts I'm...

Open the association file and split each line into an array using 'tab' as the delimiter. Starting with array element @_[2] on each line, open the referenced file and do work, then write the output...

I have not tried to execute a command within the subject line but often include variables. You can try executing the command using "`" back ticks like;

ls -otrg|awk '{print $4 " " $5 " "$6 "...

The 'sed' line replaces the first 4 numbers on a line with '/www/repository/<first_4_num>/<first_4_num> and so has no dependency on case. The for loop copies each full path including the file name,...

I would add the path and file type flags and if you want long format you will need to add exec as well. You should also validate that the files your trying to find have permissions 775, because the...

Here is a solution that does not require you to build a list of file names first. If you have a set of file types like; *.txt, *.sh etc.

for x in $(find . -name "*.txt" -exec grep -l HELLO {} \;)...

Help yourself some here, check the man page for the 'find' command. the 'cmin' argument is looking at last_changed_time and what ever process is putting the file in the directory may be keeping it's...

try this...

find ./ -name <your_file_name> -cmin +30 -maxdepth 1 -exec mailx -s "file 30 minutes old" you@mail.com {} \;

Based on your description where file1 has the original columns

sed -n '2,$p' file1 | awk '{ print NR" "$0 }' > file2

you call the function and pass arguments to it by

function get_param ()
{
arg1="$1"
arg2="$2"
test="`date`"
test2="someother string"
#export test test2
}

echo "before function get_param...

Some one who knows AWK will provide a much better solution, but I can at least provide a solution.

# # get the list of duplicates in column 2
awk '{print $2}' file | sort | uniq -c | sort -n |...

By using the 'find' command you can find files even in sub directories

ls -l $(find . -name "811_Intermediate_File_*" -exec grep -l 4400276302 {} \;)

You can use 'trap' within the parent script to capture signals and perform commands before exiting.

$ trap -l
1) SIGHUP 2) SIGINT 3) SIGQUIT 4) SIGILL
5) SIGTRAP 6)...

This will replace the space after .com .net or .org with a pipe.

sed '/req.http.host/s/\([com|net|org]\) /\1|/g' file

Not as graceful as awk but it works

sed -n -e '/^[0-9]/s/ *//gp' file | sed 's/red/red /' | sort -u

Look for all lines beginning with a number and remove all spaces
Look for lines with word...

You can get the date and time variables then extract what you want using sed

var_time=$(date '+%m/%d/20%y %k')
sed -n "/^Starting.*$var_time/,/^$/p" file

You should be able to use the app srvrs built in startup feature

asadmin start-domain --user admin --passwordfile

WHERE --passwordfile is $HOME/.asadminpassword
contents=...

Maybe this is what your looking for...

#!/bin/ksh

typeset -i record_cnt=$(grep -c "ENDC.*$sysDate" file1)
if (( $record_cnt > 0 )); then
execute_script.sh
fi

I use regular expressions in Expect and by using the wild card am able to match everything in the buffer up to the '$' prompt.

expect -re ".*\$" {
send_user "HI\n";
send "\r";
}