Search Results

Try mine. Not a one-liner though.

FILE_PATH="<write the path here>"
FILE1="${FILE_PATH}/S5_SK1.chr01"
FILE2="${FILE_PATH}/S5_SK1.chr02"
FILE3="${FILE_PATH}/S5_SK1.chr03"
BASENAME1=`basename ${FILE1}`
BASENAME2=`basename...

#!/usr/bin/sh

INPUT=$1
COUNT=${INPUT}

while [ ${COUNT} -ne "1" ]
do
COUNT=`expr ${COUNT} - 1`
INPUT=`expr ${INPUT} \* ${COUNT}`
done

echo ${INPUT}

sddDVM12312373069


echo sddDVM12312373069 | sed 's/DVM/"DVM"/' | sed 's/73069/"73069"/'


Output:

sdd"DVM"123123"73069"

The Case statement will already verify if the parameter is valid or not - whether the parameter is int or char. If the parameter is composed of characters, then the Case statement will select the (*)...

sed q | sed "s/^/'/" --> for the first line

sed '$!d' | sed "s/^/'/" --> for the last line

grep <string> $TMPFILE

cat $TMPFILE | sed '/<string>/!d'

cat $TMPFILE | sed -n '#p' ---> # refers to the line number

Maybe it's better if you use grep or sed.

Anytime.:b:

1.txt
G1='0318'
G2='0023'
G3='3092'
G4='0014'


#!/bin/sh

C=1

while read LINE
do
if [ $C -le 4 ]
then
G="G$C"
A=`echo $LINE | awk '{print substr($0,5,4)}'`
echo "Group=$G...

Search the current directory
find . -size +750k -ls

Search all directories
find / -size +750k -ls

cat <file> | tr ' ' '\n'

1.txt
I Want this line to look like this.

[******@******** home]$ cat 1.txt | tr ' ' '\n'
I
Want
this
line
to
look
like
this.

Hey man, you got the code wrong. Change the single quote in W to `.


W=`whoami`
DATE=`date "+%Y-%m-%d %H:%M:%S"`

echo " $DATE- by $W"


Output:
2011-03-29 10:18:36- by ******

This is it.


#!/bin/sh

STR=`grep $1 1.txt | awk '{ print $2 }'`

if [ -z $STR ]
then
echo "0"
else
echo $STR
fi





---------- Post updated at 04:21 PM...

Try this sir.


#!/bin/sh

STR=`grep $1 1.txt | awk '{ print $2 }'`

if [ -z $STR ]
then
echo "0"
else
echo $STR
fi

Sir, whatever the input will be, the code will output the "0".

grep -c $1 1.txt

if [ $? -ne "0" ]
then
echo "0"
else
echo $1
fi

Three separate if..else statements? Or, nested if statement? Can you please expound.

Program:

$1 can be Marcus or any input you want to find in the file

grep -c $1 1.txt

if [ $? -ne "0" ]
then
echo "0"
fi

Do you want the script in the command line or inside a program?

Don't put the awk part. Just the grep.

[******@******** home]$ grep -c "Marcus" 1.txt
0

I don't know how to display a certain string when the grep did not find a match. But the code below will output zero (instead of nothing) if there is no match.

grep -c "Marcus" list.txt

The reason why I put that script is because you didn't put the extension file in the file name.


FILE_NAME="new_applicant_list"

SCRIPT_PATH="/u01/app/banner/test/skid/plus/"
FILE_PATH="/nfs/mercury/u03/banner/test/skid/log/"
LIST_FILE_PATH="/u01/banjobs/TEST/"
SCRIPT_NAME="szpcal1.sql"
FILE_NAME="new_applicant_list"
...

Hey man, if would do this problem, I would just make a new file and append each line of both files and make an if statement. That is because I'm just a beginner. But I want to learn more about the...