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Thanks drl,

The Perl document says:

which covers this case and the result should be positive or "matching the divisor". As you point out, the Wikipedia table shows BASH gives the same sign as...

Thanks Jim, I tried that and it made no difference:


echo "The result of A % B should be an integer in the range 0 to B-1, let's test it ..."
echo "(9-7) % 5 = $(( $(( 9 - 7 )) % 5 )) (should be...

Hi,

I'm new to the Ash shell so my apologies if this is well known. In normal maths and other shells and languages I've used, the modulo operator always returns a positive remainder. For example...