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Hi,

I am stripping the below file based on a pattern:

**Starts**02-MAY-2017 03:48:13
**Ends**02-MAY-2017 03:48:13
+---------------------------------------------------------------------------+...

Thanks: Now I have done it in 2 steps:

TO_DIR=${FROM_DIR/"out/o"/"log/l"}
TO_DIR=${TO_DIR/".out"/".req"}
Can it be done in a simpler way?

Hi RudiC,

I tried with echo ${FROM_DIR//out/log}
But I cant put echo ${FROM_DIR/out/o/log/l} as it is not working

My search string as well as replace string has a / in between

Hi,

I have a variable which holds the below value:

echo $FROM_DIR
/fsg/fgldevu/fs_ne/inst/FGLDEVU_01/logs/appl/conc/out/o14946708.out

I want to change the value in the variable as below:...

Hi,

I have the below file which I need to split:

> cat file.dat
00000201703300129STK00293...

Did you tried spool /home/appusr/scripts/${dateString}_batchtest3.log

Thanks!!
YrDoy=`date '+%Y%j'` works perfectly for me!!

Thanks a lot!!
Actually, I need to derive a filename from it.

${FILE_NAME_WO_EXTN}_${year}${doy}.ZIP. Can you please help me how can I use it here

Hi,

I need to find out the day of the year and it always needs to be 3 digits:


#!/bin/ksh
doy=`date '+%j'`
let doy=$doy-1
echo doy


Output is 36, but I need it to print as 036
...

I got it:

myarray=`for file in *.txt; do awk -F'|' '$1=="\"HD\"" {gsub(/"/,"",$3); print FILENAME, $3;exit}' ${file}; done | sort -k2 | awk '{print $1}'`
for i in ${myarray[@]}
do
echo $i...

Thanks, It gives below output:


file2.txt 0000000018
file1.txt 0000000019


So I just taking the first field alone:
for file in *.txt; do awk -F'|' '$1=="\"HD\"" {gsub(/"/,"",$3); print...

This forum is not the right place to ask about Oracle concurrent programs. Yet, below is the solution for it.

There are no defined exit commands to return a warning status. However, it can be done...

Hi,

I have two pipe separated files as below:

head -3 file1.txt
"HD"|"Nov 11 2016 4:08AM"|"0000000018"
"DT"|"240350264"|"56432"
"DT"|"240350264"|"56432"

head -3 file2.txt
"HD"|"Nov 15...

Hi,

I have a data file separated by comma, data enclosed by ""

head file.txt

"HD","Sep 13 2016 1:05AM","0001"
"DT","273093045","192534"
"DT","273097637","192534"
..

I want to get the...

Thank you. It works now:

find "$INBOUND_PATH" \! -path "$INBOUND_PATH" -prune -type f -size 0 -exec sh -c 'for i do mv "$i" "'$ARCHIVAL_PATH'"; done' sh {} +

find "$INBOUND_PATH" ! -name . lists me all the files and current directory.
/home/pganesan/crypt
/home/pganesan/crypt/file1.txt
/home/pganesan/crypt/file2.txt
/home/pganesan/crypt/file_file.txt...

Can this be done without

RudiC,

I am now sure how to prepend source file. Please help on that.

Chakrapani,

I didnt went for find since the archival path is in a subfolder and it will picks up those files as well....

Hi,

I have a requirement to move zero byte files to an archive folder. I have the below script and it works fine if I run it from where the file is present. But when I run the script from...

Thanks! Works perfectly!!

Hi,

I need to download a zip file from my the below US govt link.

https://www.sam.gov/SAMPortal/extractfiledownload?role=WW&version=SAM&filename=SAM_PUBLIC_MONTHLY_20160207.ZIP

I only have...

Hi,

I need to send an email in the below format:

Hi All,

body description on 12-Dec-2014

<a html table, which is there in Result.txt file>

I am using the below command


{
echo "Hi...

Hi,

I have read & write access in Unix box A and read access in Unix box B.
I want a folder to be zipped from box B and sftp-ed in box A.

Is there a remote scripting to achieve this?

Check if the SSL certificate is valid. It may have got end-dated

Can somebody kindly help on this?