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Operating Systems Linux Red Hat copy & replace text
# 1  
Old 04-13-2011
copy & replace text
how can i copy a certain word from a text file then use this word to replace in another text file??
i tried to use something like:
Code:
awk '{print "Hit the",$1,"with your",$2}'  /aaa/qqqq.txt > uu.txt

but i can't add an argument to point to the second file which i will replace in.

please help me
Last edited by Franklin52; 04-13-2011 at 05:15 AM.. Reason: Please use code tags, thank you
# 2  
Old 04-13-2011
Can you post an example of both files and the desired output?

Please use code tags.
# 3  
Old 04-13-2011
Hi ,

if your awk script gives you the word to replace in the other file, it could be used as follow:
Code:
word_to_replace=$(awk '{print "Hit the",$1,"with your",$2}'  /aaa/qqqq.txt)

sed "s/pattern/$word_to_replace/g" file2


Hope this helps.

Regards
# 4  
Old 04-13-2011
It is the content of each file:
file1.txt:
Quote:
55:00 99:00 88:00 11:00 77:00
file2.sh: >>"a script file"
Code:
#!/bin/sh
at 11:11
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at 22:22
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at 33:33
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at 44:44
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at 55:55
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call

and the outputfile.sh will be:

Code:
#!/bin/sh
at 55:00
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at  99:00 
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at 88:00 
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at 11:00 
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call
at 77:00
cp /qq/event.call /var/spool/asterisk/outgoing/
chmod 777 /var/spool/asterisk/outgoing/event.call

---------- Post updated at 03:52 AM ---------- Previous update was at 03:38 AM ----------

Quote:
Originally Posted by cgkmal
Hi ,

if your awk script gives you the word to replace in the other file, it could be used as follow:
Code:
word_to_replace=$(awk '{print "Hit the",$1,"with your",$2}'  /aaa/qqqq.txt)
 
sed "s/pattern/$word_to_replace/g" file2

Hope this helps.

Regards
this solution in very close to what i need, but how can i replace the "pattern" in the "sed" command to be a a certain word and liene number??, for more details please see my example post.
# 5  
Old 04-13-2011
Try this:
Code:
awk 'NR==FNR{split($0,a); next}/at/{$2=a[++c]}1' file1 file2 > newfile

Last edited by Franklin52; 04-13-2011 at 06:48 AM.. Reason: Adding next statement
This User Gave Thanks to Franklin52 For This Post:
mos33
# 6  
Old 04-13-2011
Code:
xargs -n1 <file1 | nawk 'NR==FNR{A[++i]=$1}NR!=FNR{if (/^at/) sub($2,A[++j],$0); print $0}' - file2.sh >output.sh

Ok Franklin's code is better Smilie

Just need to take care about the 1 that will make the content of file1 printed as well (what we do not want)
to avoid this (assuming this file1 is just made of 1 line) you can go with :

Code:
awk 'NR==FNR{split($0,a);getline}/at/{$2=a[++c]}1' file1 file2 > newfile

Last edited by ctsgnb; 04-13-2011 at 06:42 AM..
These 2 Users Gave Thanks to ctsgnb For This Post:
Franklin52 mos33
# 7  
Old 04-13-2011
the command :
Code:
awk 'NR==FNR{split($0,a);getline}/at/{$2=a[++c]}1' file1 file2 > newfile

is very useful but still printing the content of file1 to the output, how can i avoid this??
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