Programming

Hi
i have one issue and i dont understund what hapends may be you will help me!

I have one file with name daemon_file it contains this records

aram_Load_pr-
aram_Pst-
aram_Chk-CTU

In the script i am doing like this

for daemon_row in `cat daemon_file`
do

daemon_name=`echo $daemon_row | awk '{split($1,tmp,"-");print(tmp[1])}'`
DAEMON_PARM=`echo $daemon_row | awk'{split($1,tmp,"-");print(tmp[2])}'`

done

The question is why i see in log file echo only from 2 records although in the file above i have 3 records ?

for daemon_row in `cat daemon_file`
do

daemon_name=`echo $daemon_row | awk '{split($1,tmp,"-");print(tmp[1])}'`
DAEMON_PARM=`echo $daemon_row | awk '{split($1,tmp,"-");print(tmp[2])}'`
echo $daemon_name
echo $DAEMON_PARM
done

OUTPUT:

aram_Load_pr

aram_Pst

aram_Chk
CTU


It works fine , the only mistake i noticed is there is no space between awk and ' in the second command in for loop .

try correcting that .

Thanks the log is prety big and i didnt saw the last line is printed at the botom of the log. Thanks for opening my eyes