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problem with sleep command

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# 1  
Old 08-20-2008
problem with sleep command
Hi all,
I have a following code,(linux)

#include<stdio.h>
#include<unistd.h>

int main()
{
printf("start");
sleep(3);
printf("stop");
return 0;
}


i am getting output as

first delay
startstop

not understanding why is it so rather than printing "start" and delay then "stop"
# 2  
Old 08-20-2008
Possibly because the output stream is buffered. Try putting
Code:
fflush(stdout);

after the first printf
# 3  
Old 08-20-2008
or turn off the buffering mode for STDOUT before itself

using setvbuf
# 4  
Old 08-20-2008
It is related to the output stream being buffered...fully buffered if writing to a file and line buffered if writing to a terminal. As printf() writes to a terminal the stdout stream is line buffered so all that is needed is adding a newline character to the end of the output strings.

Code:
printf("start\n");
sleep(3);
printf("stop\n");

# 5  
Old 08-22-2008
its workin, thank u



Quote:
Originally Posted by spirtle
Possibly because the output stream is buffered. Try putting
Code:
fflush(stdout);

after the first printf
# 6  
Old 08-22-2008
thanx , adding "\n" and fflush(stdout ) , both are working
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