Programming

hi .

how can I allocate a 2 dimensions array?

I used :

{
int i;

/* Allocating the rows */
Schedule = (int **)( malloc( sizeof(int*) * (N-2) ) );
if( Schedule == NULL )
{
printf("\nError - couldn't allocate memory! Aborting...\n");
exit(-1);
}
/* Allocating memory for columns */
for( i = 0; i < N - 1; i++ )
{
Schedule[i] = (int *)( malloc( sizeof(int) * N ) );
if( Schedule[i] == NULL )
{
printf("\nError - couldn't allocate memory! Aborting...\n");
exit(-1);
}
}
return;
}

end of quote!

but it doesn't allocate the array .... when I use : "Schedule[0][0] = 1;" , for example , I get "segmetation fault" .

Thanks , Azran .

You are thinking that arrays and pointers are interchangable. They are not. Read this section of the c faq. Your question is addressed in question 6.16, but you should read the entire section.

The Schedule[i][j] is a pointer.
Your allocate program is right. But you are trying to change the value of a pointer Schedule[0][0]. You may just want to change the value it points to, if you do, you coulde use:
*Schedule[0][0] = 1