inb(); not reading charaters as expected


 
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# 1  
Old 07-21-2007
inb(); not reading charaters as expected

I am sorry if this is in any way against the rules; the code isn't intended to be malicious, though it could be. If it is that bad, please delete/lock the thread instead of banning me.

So, I'm creating a keylogger, and it's not working as expected. Currently the program reads directly into the keyboard port (0x64), and then prints out that character. It echo's my characters when I type into the program, but when I type in a different program, it doesn't detect them. It's not very functional yet, but here is the code:
Code:
#include <stdio.h>
#include <sys/io.h>

#define KEYBOARD 0x64

main()
{
    unsigned char c;

    iopl(3);
    ioperm(KEYBOARD, 0, 1);

    while (c = inb(KEYBOARD))
        if (c != '4' && c != '5')    /* mouse related stuff */
            printf("%c", c);

    ioperm(KEYBOARD, 0, 0);
}

Thanks for reading/responding.
# 2  
Old 07-22-2007
What platform, operating system etc?

Sounds like the kind of thing you would put in a DOS TSR program but in UNIX this would either go into a driver, or as part of a pseudo-terminal wrapper program.
# 3  
Old 07-22-2007
I have an Intel processor, and this is under the Linux 2.6 kernel.
# 4  
Old 07-22-2007
Quote:
Originally Posted by Octal
under the Linux 2.6 kernel.
Are you writing this as a user process or part of the kernel?
# 5  
Old 07-22-2007
I'm sorry I forgot to clarify these things.

This is meant to be a user process.
# 6  
Old 07-22-2007
Quote:
Originally Posted by Octal
This is meant to be a user process.
Surely IO ports are only accessible from drivers, and user processes are isolated from the hardware?
# 7  
Old 07-22-2007
Quote:
Originally Posted by porter
Surely IO ports are only accessible from drivers, and user processes are isolated from the hardware?
If you execute the program it echoes what you type into it, so it must be reading into the hardware correctly, right?
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