Programming

combine-strings.c:4: error: syntax error before ‘char'
combine-strings.c: In function ‘combine':
combine-strings.c:7: error: ‘string1' undeclared (first use in this function)
combine-strings.c:7: error: (Each undeclared identifier is reported only once
combine-strings.c:7: error: for each function it appears in.)
combine-strings.c:9: error: ‘string3' undeclared (first use in this function)
combine-strings.c:11: error: ‘string2' undeclared (first use in this function)

#include <stdio.h>
/* #include <string.h> == cheating! */

char *combine(char string1[1000], char string2[1000] char string3[2000]) {
	int count1 = 0, count2 = 0, count3 = 0;

	while (string1[count1] != '\0') {
		++count1;
		string1[count1++] = string3[count3++];
	}
	while (string2[count2] != '\0')
		string3[count3++] = string2[count2++];
	string3[count3] = '\0';

	return string3;
}

main() {
	char string1[1000];
	char string2[1000];
	char string3[2000];
	int i = 0;
	int count = 0;
	
	printf("Enter two strings to be combined. Each under 1000 characters:\n");
	while(i == 0) {
		printf("1: ");
		gets(string1);
		while (string1[count] != '\0')
			++count;
		if (count > 1000) {
			i = 0;
			printf("I said under 1000 characters, please enter it again:\n");
		}
		else
			i = 1;
	}
	count = i = 0;
	while(i == 0) {
		printf("2: ");
		gets(string2);
		while (string2[count] != '\0')
			++count;
		if (count > 1000) {
			i = 0;
			printf("I said under 1000 characters, please enter it again:\n");
		}
		else
			i = 1;
	}
	printf("\"%s\" and \"%s\" combined are \"%s\"\n", string1, string2, combine(string1, string2, string3));
}

char * combine( char string1[1000] , char string2[1000] ) {

    int count1 = 0, count2 = 0;

    while ( string1[count1] != '\0' && count1 < sizeof (string1) )
        count1++;

    while ( string2[count2] != '\0' && count1 < sizeof (string1) )
            string1[count1++] = string2[count2++];

    if ( count1 == sizeof (string1) )
        return NULL;
    else
        string1 [count1] = '\0';

    return string1;
}