Been a while since my last post. Had a laptop die with my last project and still working to get it back. In the meantime I started another.
In my main function I define some arguments with getopt:
Code:
int main ( int argc, char **argv) {
int option_index = 0;
char *fname = "./commands";
if(argc == 1){
//pass: error defined in file_open function.
file_open(fname);
}
while(optind < argc) {
if(( option_index = getopt(argc, argv, "f:h:u:p:k:o:w:e")) != -1){
switch(option_index){
case 'f':
file_open(optarg);
break;
case 'h':
host_open(optarg);
break;
case 'u':
user_open(optarg);
break;
case 'p':
port_open(optarg);
break;
case 'w':
pass_open(optarg);
break;
default:
usage();
break;
}
}
else {
file_open(fname);
optind++;
}
}
return 0;
}
The above is missing some optional arguments for brevity. Since there were optional arguments, I found I would need to use a variadic function with something like this:
Code:
void args(char *howmany, ...){
va_list ap;
char *host, *user, *pass, *port;
va_start(ap, howmany);
while(*howmany) {
switch(*(howmany++)){
case 'h':
host = va_arg(ap, char *);
printf("%s\n", host);
break;
case 'u':
user = va_arg(ap, char *);
printf("%s\n", user);
break;
case 'w':
pass = va_arg(ap, char *);
printf("%s\n", pass);
break;
case 'p':
port = va_arg(ap, char *);
printf("%s\n", port);
break;
}
}
va_end(ap);
}
Looking at these I could see they were very similar with their switch statements. Instead of calling a function from main and then using that function to call the variadic function, it seems there should be a way to combine them. I'm just having trouble getting the logic/syntax for this and not finding much with my google searches.
Your question is not clear at all. In first code Input arguments are always defined in the variable argc. In the second example, the parameters for the 64-bit system are enumerated. Since the transition from 32 to 64-bit broke the compatibility of the transfer in a function an indefinite number of parameters. Some parameters were passed to the function through the registers and not through the stack. Therefore, macros were invented va_list, va_start, va_end. These are all different things. Choose what you need.
main and getopt aren't variadic, they're array-based.
So one solution could be converting the variadic arguments into an array.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <stdarg.h>
void argfunction(char *howmany, ...);
int main(void) {
argfunction("abc", "atext", "btext", "ctext");
return(0);
}
void argfunction(char *howmany, ...)
{
int n=0;
// Never forget the NULLs, they convert mysterious "why" errors
// into "oh, I forgot to assign X" errors
char *host=NULL, *user=NULL, *pass=NULL, *port=NULL;
int argc=0;
char *argv[16];
va_list ap; // IIRC ap should always be the very last variable declared in a function.
va_start(ap, howmany);
argv[0]=""; // just tradition, argv[0] in main() is not an argument
// checks howmany[0], assigns argv[1].
// checks howmany[1], assigs argv[2], etc.
while((argc<(16-2))&&howmany[argc++]) argv[argc]=va_arg(ap, char *);
argv[argc]=NULL; // Also traditional that argv[argc] be NULL.
va_end(ap);
printf("Howmany is: %s\n", howmany);
printf("Arguments are:\n");
for(n=1; n<argc; n++)
printf("\t%d\t%s\n", n, argv[n]);
optind=1; // This is global, so reset it
// You now have argv, argc, and optind just like main to feed getopt with.
}
Last edited by Corona688; 02-20-2019 at 04:07 PM..
I guess I didn't explain things well. I assumed using a variadic function would be the only way to get optional and required parameters. I tried to implement the code from Corona688 in my own, but could not get it to work. I did more searching and came back to example 2 on this page I had been to before:
Hi All,
An old work friend wrote a script which I've been trying to understand how a section of it currently works and work out how i can add some command line switches which i can use later in the script to append the output depending on the command line arguements.
Currently it works by... (1 Reply)
Hi,
I want to use the getopt function to parse some arguments for a script.
while getopts "i:f:r:" OPTION
do
case $OPTION in
i) iter=$OPTARG;;
f) frame=$OPTARG;;
r) roi=$OPTARG;;
?) echo Usage: ......
exit 2;;
esac
done
However, I... (5 Replies)
I m trying to use getopt
This is my script, but it doesn't take argument in variable,
Please help.
set - - `getopt mscl: $*`
if
then
echo "Exiting...."
exit 2
fi
for i in $*
do
case $i in
-m) MAIL="$i"; shift;;
-s) SCRIPT=$OPTARG; shift;;
-c) COB=$OPTARG; shift;;... (2 Replies)
#!/bin/sh
set -- `getopt "abco:" "$@"`
a= b= c= o=
while :
do
case "$1" in
-a) a=1;;
-b) b=1;;
-c) c=1;;
-o) shift; o="$1";;
--) break;;
esac
shift
done
shift # get rid of --
# rest of script...
# e.g.
ls -l $@ (6 Replies)
scriptname
i have made a script to perform so tasks and i managed to complete the tasks for all the options
the problem i am facing is that i can run the scripts individually but i would like to make it such that it can accept multiple options and give me the appropriate output
e.g.... (1 Reply)
I'm using getopt() to get command line options.One the optons accepts and argument.The argument is and offset.I was wondering how can I scecify that it's argument is of the type off_t.I've something like this "offset=(off_t)optarg" and it don't work. (1 Reply)