C++ : Base class member function not accessible from derived class


 
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# 1  
Old 07-22-2014
C++ : Base class member function not accessible from derived class

Hello All,
I am a learner in C++. I was testing my inheritance knowledge with following piece of code.

Code:
#include <iostream>

using namespace std;

class base
{
	public :
		void display()
		{
			cout << "In base display()" << endl;
		}
		void display(int k)
		{
			cout << "In base display(int k)" << endl;
		}
};

class derived : public base
{
	public :
		void display()
		{
			cout << "In derive display()" << endl;
		}
};

int main()
{
	derived der;	
	der.display(50);
}


As far as I know it should compile without giving any error. But that is not the case as it is giving compilation error saying :-

Code:
StaticMember_1.cpp: In function ‘int main()':
StaticMember_1.cpp:30: error: no matching function for call to ‘derived::display(int)'
StaticMember_1.cpp:21: note: candidates are: void derived::display()

Can you guys help me out in finding why its giving error. there must be some concept here which I am missing.
Thanks in advance all of you.

Regards,
Anand Shah
# 2  
Old 07-22-2014
When you declaredisplay() in the derived class, it hides the base class display() instead of overloading it. So when you call the display() using a derived class object, you will get an error since the compiler is unable to find the correct function.

Refer C++ FAQ for more info.
This User Gave Thanks to chacko193 For This Post:
# 3  
Old 07-22-2014
Thank you Chacko193 for your efforts. I understood it completely. I always felt there is some catch in it which I was missing. Thanks again.
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