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Hexadecimal to binary operation

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# 1  
Old 05-13-2014
Hexadecimal to binary operation
Dear all,
I am trying to write c-program [2] to read the following file [1] containing hexadecimal values (snippet of big data file).
I want to combine two hexadecimal values together like A0A03E01 and then would like to have the binary equivalent to perform further test on it. Unfortunately, it failed to give me binary equivalent.

This project is kind of urgent for me, any help is highly appreciated.

thanking you very much,
emily,

[1]
---------------------------
Code:
file.dat:
0x1A0A0
0x13E01
0x10400
0x12A03
0x1C010

[2]
--------------------------
Code:
#include <iostream>
#include <fstream>
#include <sstream>
#include <bitset>
#include <string>
#include <limits>
#include <stdlib.h>
using namespace std;

int main(int argc, char *argv[])
{
  string data16, data32;
  unsigned value;
  bool dodebug = true;

  //open datafile
  std::fstream datafile;
  datafile.open("file.dat",std::fstream::in);

  stringstream ss;
  while(!datafile.eof()) {
    ss.clear();
    datafile >> ws;
    datafile >> data16;
    datafile >> data32;
    if(dodebug)   cout<<"data :"<< data16<< ", "<< data32<<endl;
    
    ss << std::hex << data16 << data32;
    ss >> value;
    bitset<32> data(value);
  }
}

# 2  
Old 05-13-2014
How do you intend to combine two 20-bit numbers into one 32-bit number?

Anyway:

Code:
#include <stdio.h>

int main(void) {
        char buf[512];
        unsigned int v;

        while(fgets(buf, 512, stdin))
        {
                if(sscanf(buf, "0x%05x", &v) != 1)
                {
                        fprintf(stderr, "Unable to parse line '%s'\n", buf);
                        continue;
                }

                printf("Got hex value %x = decimal value %d\n", v, v);
        }
}

Run it like ./program < inputfile
This User Gave Thanks to Corona688 For This Post:
emily
# 3  
Old 05-13-2014
Dear Corona,
Thank you for your reply.
However, I realized that the data format is differently written [1] and should be read different [2]. So in principle, I need to read the first column of file[1] as this way [2] avoiding the rest of the columns. And then it solve the problem. So I would like to add this feature in coding to read it like [2].

Please suggest if this is possible.


Thanks again,

Code:
[1]
file.dat:
0x1A0A0 0x10000 0x1A480 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 
0x13E01 0x10000 0x12801 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 
0x10400 0x10000 0x10410 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 
0x12A03 0x10000 0x12203 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 0x3FFFF 

[2]
file.dat:
A0A0
3E01 
0400 
2A03

Last edited by emily; 05-13-2014 at 07:33 PM..
# 4  
Old 05-14-2014
The given code will still work even after you have made the said changes to the input file. if you only want the four hex digits, make the following change:
Code:
if(sscanf(buf, "0x1%04x", &v) != 1)

# 5  
Old 05-14-2014
Dear Chacko,
Thanks for reply. I wonder what is 'buf' here?

emily

---------- Post updated at 02:47 AM ---------- Previous update was at 02:43 AM ----------

I tried to use it like
Code:
 while(!datafile.eof()) {
    if(sscanf(datafile, "0x1%04x", &v) != 1) {

It complain about

Code:
error: ‘v' was not declared in this scope
make: *** [all] Error 1

thanks
# 6  
Old 05-14-2014
buf is the variable where you store the line read from the file. But in the code you gave, datafile is a fstream object, not a character array.

Can you provide the enitre code?
# 7  
Old 05-14-2014
Hello,
Plese find the entire code:
thanks

Code:
#include <iostream>
#include <fstream>
#include <sstream>
#include <bitset>
#include <string>
#include <limits>
#include <stdlib.h>
using namespace std;

int main(int argc, char *argv[])
{
  string data16, data32;
  unsigned value;
  bool dodebug = true;

  //open datafile
  std::fstream datafile;
  datafile.open("file.dat",std::fstream::in);

  stringstream ss;
  while(!datafile.eof()) {
    ss.clear();
    datafile >> ws;
    datafile >> data16;
    datafile >> data32;
    if(dodebug)   cout<<"data :"<< data16<< ", "<< data32<<endl;
    
    ss << std::hex << data16 << data32;
    ss >> value;
    bitset<32> data(value);
  }
}
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