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*** glibc detected *** ./a.out malloc() memory corruption

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Top Forums Programming *** glibc detected *** ./a.out malloc() memory corruption
# 8  
Old 06-25-2013
The problem is that the second loop does not even open the file fp for reading. I have checked it by doing the following:

Code:
for(z=0;z<2;++z)

           {
              printf("@@@@@@@@@@@@@@@@@@@@@@@@@\n");
             fp=fopen("poly.dat","r");

             ......

              }

For z=0, printf statement gets executes while for z=1, this does not happen. So even the file fp is not opened for reading.

Moderator's Comments:
Mod Comment Please use CODE tags; not ICODE tags for multi-line blocks - Last Reminder - Infractions come next.
# 9  
Old 06-25-2013
Because of buffering, printf is insufficient to determine if fopen was reached. Use strace or similiar to monitor open() syscalls.

Did you try recompiling without the pointless fseek which immediately follows fclose?

Regards,
Alister
Last edited by alister; 06-25-2013 at 12:41 PM.. Reason: typo
# 10  
Old 06-27-2013
I tried the code without using fseek but same thing happens.....as I am still in a nascent stage of learning, I am unable to ascertain the usefulness of strace....any help would be great.
# 11  
Old 06-27-2013
Hmmm. With your code I was able to reproduce the malloc() corruption error; removing the fseek() call with the pointer to memory free()'d by fclose() fixed the issue.

Regards,
Alister
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