Assembly 8085


 
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# 8  
Old 05-20-2012
One last question on this.. Kind of stuck in that:
What is the routine, if my equation is n = 1 - i^2 ?
I'm a little new handling minus numbers in hex.
Maybe, something with MSB bit which is the sign (+/-) when we have a minus number?
Smilie
# 9  
Old 05-23-2012
Quote:
Originally Posted by giampoul
One last question on this.. Kind of stuck in that:
What is the routine, if my equation is n = 1 - i^2 ?
I'm a little new handling minus numbers in hex.
Maybe, something with MSB bit which is the sign (+/-) when we have a minus number?
Smilie
The 8085 uses 2s complement to represent negative numbers...so knowing that negate i^2 by inverting it and adding 1 to it followed by adding 1 again to represent the equation "n=1-i^2"...and in the final step display the result by taking the 2s complement of n.
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