Programming

This gives :
after calling it twice:
how can i solve this so that on output i get :

standard input is getting buffered.

To resolve , you should stop stdin buffering. Try the following
setbuf(stdin,NULL) after scanf statement.

Moreover, atoi expects a character pointer or string. So, when you type 6 and Enter(i.e. NL) NL which is 10 in decimal is getting buffered. Due to this 10 which satifies your while loop, it is displaying twice.

setbuf(stdin,NULL);
hasnt changed anything
can you be more precise please

I'm not sure that I understand what you want, but try a flush after the scanf:

scanf("%c",&car);
fflush(stdin);

In my previous reply I mentioned the reason for displaying twice i.e. buffering stdin is on by default, this you can do off

by either setbuf(stdin,NULL) or fflush(stdin)

Even I checked the above on my m/c (solaris 8), it was working fine.

(OR) try the following

In the while loop, instead of 9 give 10 or greater because NL(New Line) has the value ASCII 10

while ((ent<5) || (ent > 11) )

ive rewritten the code !!!

output:
as u can c, i want the value entered to be integer and be between 3 and 10
if not asks again
when id entered 3 it repeats the question
but when its 34, it asks the question without waiting for input

atoi needs a string not a character. You can convert a single character to a digit by subtracting '0'. Also when you type, say, "1\n" in response to the first question, the \n remains to be used in the next scanf. Some platforms will flush left overs if you fflush(stdin), but it's not universal. Try:

Code:

#include <stdio.h>
int main () {
char coll;
int col;

do {
    printf("Enter Number: \n");
    scanf(" %c",&coll);
    col = coll - (int)'0';
    } while (( col < 4 ) || (col > 9));
}