problem in multiplying arrays


 
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# 15  
Old 12-05-2011
You use a(i,j) in many places you should be using A(i,j).
This User Gave Thanks to Corona688 For This Post:
# 16  
Old 12-05-2011
pff
problems appear again..
the error is gone,also a and b arrays are right but i c give me 0 in every i,j .
i think i call the arrays wrong at compute.c:
Code:
int *a,*b,*c;
a=(int *)shmat(id,NULL,0);

b=(int *)shmat(id,NULL,0);

c=(int *)shmat(id,NULL,0);

is this the right way or i have to call the arrays like in the main ??
# 17  
Old 12-05-2011
As explained many times in the last 2 pages, that sets all three arrays to the SAME MEMORY. It doesn't matter where you put that wrong code, it doesn't make it right code.

Code:
int *A=shmat(...);
int *B=A+(2*3);
int *C=B+(3*4);

This User Gave Thanks to Corona688 For This Post:
# 18  
Old 12-05-2011
Quote:
Originally Posted by Corona688
As explained many times in the last 2 pages, that sets all three arrays to the SAME MEMORY. It doesn't matter where you put that wrong code, it doesn't make it right code.

Code:
int *A=shmat(...);
int *B=A+(2*3);
int *C=B+(3*4);

ooo
sorry!

i try it this way too but i forgot a line with shmat and it gave me only zeros.
Thanks for everything, now i have to work for the other...
Thanks for your time!Smilie
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