Programming

#include<iostream>
using namespace std;
double a,x;
double f(double x)
{
    return ((x*x)-2);
}                                         //Suppose the function is (x*x)-2.
void calcx(double a1,double b1)
    {
        x = (a1+b1)/2;
        while((f(x)*f(a))!=0)                //If f(x)*f(a)=0, then the root is 'x' itself!
        {
            if(f(x)*f(a) < 0)
            {
                if(x==1.41421509)                               //The answer should be 1.414... so given like this!
                {
                    cout<<"Process completed!";
                    cout<<"Result is: "<<x;
                }
                a1=x;                                       //The value 'a' is replaced by x and 'b' remains the same.
                calcx(a1,b1);                               //Then, we'll do recurrsion for range (x,b)
            }
            else if(f(x)*f(a) > 0)
            {
                if(x==1.41421509)
                {
                    cout<<"Process completed!";
                    cout<<"Result is: "<<x;
                }
                b1=x;
                calcx(a1,b1);                               //Here, recurrsion is done for range (a,x).
            }
        }
    }
int main()
{
    double b,res;                               
    cout<<"Enter the values of 'a' and 'b': ";
    cin>>a>>b;                                            //The range already given.
    calcx(a,b);
    return 0;
}

if(fabs(x-1.41421509) < .001)

do
{
    // Calculate result
    // Set new ranges
    // Only if not precise enough, loop through again
} while(fabs(x-1.41421509) >= 0.001);