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Old 10-14-2011
memcpy error
I am getting segmentation fault in memcpy.I have given sufficient memory but i dont know why it is occurring

Code:
char *finalptr = ( char *)malloc(1048576* sizeof(char));
finaloffset=0;have=685516;
memcpy(&(finalptr)+finaloffset,out,have);
finaloffset=685516;have=359910;
memcpy(&(finalptr)+finaloffset,out,have);

The first time it copies successfully but second time it gives segmentation fault

Code:
signal SEGV (no mapping at the fault address) in memcpy%sun4v-hwcap3 at 0xffffffff7f01b874
0xffffffff7f01b874: memcpy%sun4v-hwcap3+0x0604: stx      %o4, [%o0 - 8]t.

By calculation I am not crossing boundary but it is giving error
OS:Solaris
Last edited by pludi; 10-14-2011 at 08:02 PM..
 
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LEARN ABOUT SUSE

memcpy

MEMCPY(3)						     Linux Programmer's Manual							 MEMCPY(3)

NAME

       memcpy - copy memory area

SYNOPSIS

       #include <string.h>

       void *memcpy(void *dest, const void *src, size_t n);

DESCRIPTION

       The memcpy() function copies n bytes from memory area src to memory area dest.  The memory areas should not overlap.  Use memmove(3) if the
       memory areas do overlap.

RETURN VALUE

       The memcpy() function returns a pointer to dest.

CONFORMING TO

       SVr4, 4.3BSD, C89, C99, POSIX.1-2001.

SEE ALSO

       bcopy(3), memccpy(3), memmove(3), mempcpy(3), strcpy(3), strncpy(3), wmemcpy(3)

COLOPHON

       This page is part of release 3.25 of the Linux man-pages project.  A description of the project, and information about reporting bugs,  can
       be found at http://www.kernel.org/doc/man-pages/.

								    1993-04-10								 MEMCPY(3)