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Preprocessor __FILE__ for Debugging

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# 1  
Old 09-21-2011
Preprocessor __FILE__ for Debugging
Hi,

Just wondering if it is possible to trim the file path output by __FILE__ preprocessor in my debugging line.

Let's say my main.cpp file is found in C:\User\MyName\SystemA\Mod1\SubMod2\Test\main.cpp

for __FILE__, I just want the filename - main.cpp to be printed, instead of the entire path + filename.
# 2  
Old 09-21-2011
see Man Page for basename (Linux Section 3) - The UNIX and Linux Forums
# 3  
Old 09-21-2011
That won't work inside C, frank_rizzo.

There's not another predefined variable for the name minus path, but you can 'cheat' by altering it with a #line directive:

Code:
#line 1 "filename.c"
// rest of file

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