Programming

i tried this programme without using case... but can't seem to function it using the case function ..

#include <stdio.h>
#include <stdlib.h>
/*bytes_to_mb.c*/
/* figure out du space by converting bytes to mb using 1000*1000 standard*/
long int mb=1000*1000;
long int number;
char M;
float x,y;
float z;
int main(int argc, char *argv[])
{
{
printf("enter number to convert\n");
scanf("%ld", &number);
}
printf("for 1000*1000 output type M or else type enter\n");
scanf("%c", &M);
switch $*
case M:
x=number;
y=mb;
z=x/y;
printf("%f / %f = %.3fMB\n", x, y ,z);
printf("1000 block output\n");
break;
case :
y == 1024*1024
x=number;
z=x/y;
printf("%f / %f = %.3fMB\n", x, y. z);
printf("1024 block output\n");

fflush(stdin);
getchar();
return (0);
}

this is the errot output:
bytes_to_mb2.c: In function `main':
bytes_to_mb2.c:18: error: syntax error before "$"
bytes_to_mb2.c:26: error: syntax error before ':' token
bytes_to_mb2.c:30: error: request for member `z' in something not a structure or union
bytes_to_mb2.c:30: warning: too few arguments for format
bytes_to_mb2.c:25: error: break statement not within loop or switch


i have tried several different combinations including an if else clause instead of using case but can not seem to get it to work..
very frustrated!!
moxxx68

Moxx,

At the bottom of your post you will find your compilation errors. Please run a google search to see if you can find resolution to the errors. Namely, have a look at switch. Shell and C syntax are not the same, you dont use $ in C as you do in Shell. The second to last printf statement has a typo in it, you use a "." where you should be using a ",". Your format of the switch statment is not correct. Also, be careful about your variable definitions, make sure that they are consistent throughout your program. And, it looks like you intended a loop but forgot the while ( ) statement.

C, like all other languages, has a specific syntax that you must comply with when developing. The compiler will let you know when you have it wrong. The best way to learn to develop software is to first attempt to understand what it is that you've done wrong, then try and fix it yourself. From what you posted, it appears that you would benefit from picking up an Introduction to C book. There are several noted on these boards, have a look for C books.

just trying to teach myself some basic C.. i have done a little reading in the last year but haven't actually tried any hands on programming so I thought this might be a good time to start.. basically the programm is supposed to make figuring a few numbers in accordance with other scripts and "totals^" a little more convenient since I find these numbers have my head spinning a little sometime.. I am still not quite sure about block sizes and stuff.. this way I can figure it out.
I have a few C reference guide downloads from google.. i know it sounds funny but its kind of like cheating when your'e writing a programm for the first time and have to look at the reference guide so I thought I would ask.. . i shall return to the books and examples though.
thanx moxxx68

It's "cheating" to look at a reference guide, but it's ok to ask us...

I was able to see what you were trying to do so I corrected the code somewhat. It will compile and run anyway...

Code:

#include <stdio.h>
#include <stdlib.h>
/*bytes_to_mb.c*/
/* figure out du space by converting bytes to mb using 1000*1000 standard*/
#define mb1 (1000*1000)
#define mb2 (1024*1024)
int main(int argc, char *argv[])
{
        char buff[80];
        long int number;
        char M;
        float x,y;
        float z;
        setvbuf(stdout, NULL, _IONBF ,0);
        printf("enter number to convert\n");
        fgets(buff,80, stdin);
        sscanf(buff, "%ld", &number);
        printf("for 1000*1000 output type M or else type enter\n");
        M=getchar();

        switch (M) {
                case 'M':
                        x=number;
                        y=mb1;
                        z=x/y;
                        printf("%f / %f = %.3fMB\n", x, y ,z);
                        printf("1000 block output\n");
                        break;
                default:
                        y=mb2;
                        x=number;
                        z=x/y;
                        printf("%f / %f = %.3fMB\n", x, y, z);
                        printf("1024 block output\n");
                        break;
        }

        return (0);
}

I kindly suggest that, in both the short and long run, you will get better results, make more net friends, and get more solid help if you kindly value others time by reading the reference material first and asking questions second.

Keep up the good work!

Neo