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How to grep the particular string?

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# 1  
Old 07-18-2011
How to grep the particular string?
Hi,
I have one xml file. In that file, I have <name> and <description> . I need this name and description details alone and put it in one file.
Please find the example below:

<name>This is a file name</name>
<description>Latest Release 1.0.2.0</description>

The above tags are come in the xml file. So I need to create file which contains "This is a file name" and "Latest Release 1.0.2.0" alone.
Please suggest how to do it..


Thanks

Chella..
# 2  
Old 07-18-2011
sed is the tool for this:

Code:
sed -e 's/<name>\(.*\)<\/name>/\1/g' -e 's/<description>\(.*\)<\/description>/\1/g' file.xml > newfile.txt

This User Gave Thanks to jostber For This Post:
zius_oram
# 3  
Old 07-18-2011
For simple tasks, these may be fine.

But for more XML parsing, go for a scripting language.
# 4  
Old 07-18-2011
Thanks for your quick reply. Ya. I need this activity for multiple files... How can we implement this in script???

---------- Post updated at 06:09 PM ---------- Previous update was at 06:05 PM ----------

And , if i use the above command, i will get the entire xml file. Because in that file, i have some other details are tagged in that. Could you please advice me how to get only those two details???
# 5  
Old 07-18-2011
xmlint can do the job. Of course a high level scripting language like perl, python can do a much better job

Code:
$ cat a.xml
<?xml version="1.0"?>
<doc>
<name>
Doc Name
from a.xml
</name>
<description>
Doc Description
from a.xml
</description>
<others>
Other info
</others>
</doc>

$ name=`echo "xpath //name/text()" | xmllint --shell a.xml | sed -n 's/.*content= \(.*\)/\1/p'`

$ description=`echo "xpath //description/text()" | xmllint --shell a.xml | sed -n 's/.*content= \(.*\)/\1/p'`

$ echo $name
Doc Name from a.xml

$ echo $description 
Doc Description from a.xml

Just use a for loop to do for multiple files, I will leave this to you to finish off the rest of the script.
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