Class Pointer initialization C++


 
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# 8  
Old 05-04-2011
Now you've turned it from invalid syntax, into something that's likely to crash... Think about what you're doing: You're trying to assign the contents of an unassigned pointer to NULL -- in other words, picking some random, arbitrary bit of memory and trying to write 0 into it.

Fortunately, this is a compiler error anyway since 0 isn't a ClassA.

How about:

Code:
classA *point=NULL;

NULL is like zero, but is of type void, which C++ won't complain about.
# 9  
Old 05-04-2011
Allright, my C++ knowledge are definitively rusty... But I believe, there is a slight inaccuracy in the statements claimed.

Code:
ClassA *point;
point = 0;
point = new ClassA;

Quote:
Originally Posted by Corona688
Of course they're not the same, one of them isn't even valid C++ syntax.
What let you believe this? Using 0 for NULL is perfectly legal in C++, there are actually equal. Stroustrup himself prefers to use "0": Should I use NULL or 0

This line may also work:
Code:
point = new ClassA;

as long as the ClassA provides a default constructor.

Cheers, Loïc
# 10  
Old 05-04-2011
Quote:
Originally Posted by Loic Domaigne
Using 0 for NULL is perfectly legal in C++
Even though any other integer isn't. Hooray, more weird special cases to learn in the C++ language Smilie

Naturally he'd prefer to use 0, and so not need to include stdio.h, but it's a strange inconsistency for the C++ language to let you assign 0 when it refuses to let you assign any other integer pointer value. That's what the void type used to be for, which is what NULL was of..
# 11  
Old 05-05-2011
Quote:
Originally Posted by Corona688
Even though any other integer isn't. Hooray, more weird special cases to learn in the C++ language Smilie

Naturally he'd prefer to use 0, and so not need to include stdio.h, but it's a strange inconsistency for the C++ language to let you assign 0 when it refuses to let you assign any other integer pointer value. That's what the void type used to be for, which is what NULL was of..
As you mentioned already, C++ is a strongly typed language (or a least claims to be so).
If you try the following assignment:
Code:
ClassA* point = ((void*) 0); // ((void*)0) is the C definition for NULL

Then the compiler shall complain that you're trying to perform an invalid conversion from void* to ClassA* ...

Loïc
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