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help with gcc warning

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# 1  
Old 12-10-2009
help with gcc warning
I get the following gcc warning. I do not see a double being declared anywhere... how can I fix this?

(This code is just an example, I realize that the first if bracket will never be executed.)

Quote:
a.c:18: warning: conversion to ‘float’ alters ‘double’ constant value
Code:
#include <stdio.h>

int main(void)
{
    float A = 0.0;
    int B = 150;

    if(B == 0)
    {
        A = 0.0;
    }else if(B <= 200)
    {
        A = 1.95;
    }

    return 0;
}

Last edited by limmer; 12-10-2009 at 10:14 AM..
# 2  
Old 12-10-2009
Any literal constant real numbers are double by default (with gcc I'm sure, might even be C89 standard). You've got to explicitly tell it that it's only a float by appending the identifier 'f', eg:
Code:
A = 1.95f;

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