10 More Discussions You Might Find Interesting
1. UNIX for Beginners Questions & Answers
Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
header_date_14=$(m_dump... (8 Replies)
Discussion started by: ektubbe
8 Replies
2. Shell Programming and Scripting
Hi All,
How to pass date variable to a query?
I have tried the below one , but it's not working.
ost.ksh
#!/bin/ksh
v_date=$1
var=$(sqlplus -s $ORACON <<ENDOFSQL
SELECT TO_DATE('$v_date','DD-MON-YYYY'),-1) FROM DUAL;
exit;
ENDOFSQL
)
#End
I have executed as below. (7 Replies)
Discussion started by: ROCK_PLSQL
7 Replies
3. Red Hat
Hi all,
Hereby wish to have your advise for below:
Main concept is
I intend to get current directory of my script file.
This script file will be copied to /etc/init.d.
A string in this copy will be replaced with current directory value.
Below is original script file:
... (6 Replies)
Discussion started by: cielle
6 Replies
4. Shell Programming and Scripting
Hello again :)
Am currently trying to write a function which will delete a record from a file.
The code currently looks as such:
function deleteRecord() {
clear
read -p "Please enter the ID of the record you wish to remove: " strID
... (2 Replies)
Discussion started by: U_C_Dispatj
2 Replies
5. Shell Programming and Scripting
Hello expert.
I have a little problem here.
I write a script and stuck some bug to fix.
I found the problem was about * and a sample of script is below.
line 1 is print * out
but line 3 print all name of files in the script's path. (but I want *)
I want to contain * in variable... (3 Replies)
Discussion started by: MaYuMi
3 Replies
6. Shell Programming and Scripting
Please help. I got these error. I'm try to pass variable extract from data-file.txt to sql file(select.sql).
cat: cannot open select
cat: cannot open *
cat: cannot open from
cat: cannot open user
cat: cannot open where
cat: cannot open name=$list;
#!/bin/bash
list=`sed q... (3 Replies)
Discussion started by: killboy
3 Replies
7. UNIX for Dummies Questions & Answers
Hi,
I have a master BASH shell script where I define a bunch of variables:
$var1=why
$var2=is
$var3=(this so hard)
I would then like to call another shell script and pass these variables to it:
$script2 $var1 $var2 $var3
This works fine for var1 and var2. However, var3 is an array,... (9 Replies)
Discussion started by: msb65
9 Replies
8. UNIX for Dummies Questions & Answers
I have an awk statement where I Need to pass an environment variable but I cannot get it to work:
My evironment varible examples below:
$FILE1=/dev/fs/file.new
$FILE2=/dev/fs/file.old
Code below:
awk -F"|" '
BEGIN {
while( getline < "$FILE1" )
{ arr=1 }
}
arr != 1 { print }
'... (12 Replies)
Discussion started by: eja
12 Replies
9. UNIX for Dummies Questions & Answers
i would like to pass a variable to awk wherein the variable comes from external loop.
i tried this...
let x=0
until test $x -eq 32
do
cat file | awk '{ print $1 , "Number" , $($x) }' >> output
done
thanks, (4 Replies)
Discussion started by: inquirer
4 Replies
10. Shell Programming and Scripting
Hi there. If variables are named inside of a ksh script, how is it possible to pass these to sed?
The affected portion of my script goes something like this:
A=`cut -d. -f1 $FILE`
B=`cut -d. -f2 $FILE`
C=`cut -d. -f3 $FILE`
sed 's/1111/$A/g;s/2222/$B/g;s/3333/$C/g' file > anotherfile
... (2 Replies)
Discussion started by: kristy
2 Replies
