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How to deal with this error: floating constant exponent has no digits

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# 1  
Old 10-24-2009
How to deal with this error: floating constant exponent has no digits
A conditional statement cause it:

if(strlen(str) < n1+1) {

-------

}
# 2  
Old 10-26-2009
Is this a compile-time or run-time error? I'm assuming run-time, and if so, that's probably because str is not a valid string somehow. Without seeing the code in context this is only a guess.
# 3  
Old 10-28-2009
Thanks

compile-time error.

for example:

int d (char *str1, char *str2, int n1, int n2, int len) {


if (strlen(str1) < n1+1en-1 || strlen(str2) < n2+len-1) { // Error ?

......................................
}

.....................................
}
# 4  
Old 10-28-2009
What version of GCC are you using? What headers are included?
This error is normally associated with hexadecimal floating constants or literals.
# 5  
Old 10-28-2009
gcc version 3.2.3 20030502 (Red Hat Linux 3.2.3-59)

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>
#include <string.h>
#include <stdarg.h>

thanks
# 6  
Old 10-28-2009
Quote:
Originally Posted by cdbug
Thanks


if (strlen(str1) < n1+1en-1 || strlen(str2) < n2+len-1) { // Error ?


}
You typed "1en" (one-e-n) instead of "len" (el-e-n).
# 7  
Old 10-29-2009
Sigh!! What an error!! But the two characters are the same in this shell.

Thanks
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