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C programming working with multidimensional array

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# 1  
Old 03-12-2009
C programming working with multidimensional array
Hi,
I have the following variable declaration which looks like a 3d array or N matrixs KxK of floats
float (*table[N])[K];
I have to pass to a function only the first table.
How can I do it??
Thanks
# 2  
Old 03-12-2009
Pass the first element table[0] which is the first table to the function.
# 3  
Old 03-13-2009
What should the formal parameter be?? I tried
float **table
but doesn't work
# 4  
Old 03-13-2009
Quote:
Originally Posted by littleboyblu
What should the formal parameter be?? I tried
float **table
but doesn't work
What do you mean by formal parameter. In caller the called function takes arguments and in the called those arguments are known as parameters. If x calls y then...
Code:
/* 
 * table: an array[N] of pointers to an array[K] of floats
 * table[0]: pointer to an array[K] of floats
 */
x() {y(table[0]);}

y(float (*pf)[K]) {}

# 5  
Old 03-13-2009
ok, it works fine. thanks very much. Could you explain me why
Code:
y(float **pf){}

is not correct and in which cases i have to use it?
# 6  
Old 03-13-2009
Quote:
Originally Posted by littleboyblu
ok, it works fine. thanks very much. Could you explain me why
Code:
y(float **pf){}

is not correct and in which cases i have to use it?
float **pf is not correct because it is a pointer to pointer to float i.e. dual level pointer while each element of the array table is a pointer to an array of floats...
Code:
x()
{
  float x;      /* x is a variable of type float */
  float *pf;    /* pf is a pointer to float */
  float **ppf;  /* ppf is a pointer to pointer to float */

  pf = &x;      /* pf now points to x */
  ppf = &pf;    /* ppf now points to pf */
}

# 7  
Old 03-14-2009
ok, thanks very much.
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