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Hello green_k,

Could you please try following.


awk '
/^\[/{
if(count){
for(i=1;i<=count;i++){
print val,a[i],count
}
}
val=$0
count=""
next
}
{
...

Hello green_k,

Could you please try following.


awk '/^\[/{val=$0;next} {print val,$0}' Input_file


On Sun o.s use nawk in place of awk.

Thanks,
R. Singh

Some awk versions have a problem with parsing a complicated FS.
The following variant takes a simple FS:
awk -v want="CITY,REGION,STREET" '
function prnsection() {
if (length(section)) {
...

On Sun OS you need to use nawk or /usr/xpg4/bin/awk as the legacy Solaris awk is missing many POSIX features.

Glad to explain what is going on in this code. Working thru and understanding is a great way to improve your awk skills.

Field separator RE [=\\][]

This is a simple bracket [] expression and...

And another awk approach:

awk -v want="VALUE1,VALUE2,VALUE3" -F'[=\\][]' '
function prnsection(i) {
if(length(section)) {
printf "%s",section;
for(i=1;i in keypos;i++) {
...

Here is one approach using awk:-
awk -F= '
/section/ {
sc = $1
S[sc]
next
}
/^VALUE/ {
A[sc FS $1] = $0...

Not quite there $1 contains the variable name and is overwritten with "=" newvalue, try:

awk -F= -v var="$new_value" '/ABCD/ {$2 = var} 1' OFS== file > new_file

simplified and fixed:

awk -F= -v var="$new_value" '/ABCD/ {$1= "=" var} 1' file > new_file

You can redirect the output to a new file. If ok you can replace the old file with the new file:

nawk -F"=" '/ABCD/ {print $1"=value"}' file > newfile

"collating sequence" is the key!
While most language (locale) settings in Unix are based on the ASCII sequence (numbers before characters), IBM seems to stick to the EBCDIC sequence (numbers after...

Hi Don, thanks for the explanation.
awk 'BEGIN {FS=OFS=","} /^T/ {$2=length(A)} !A[$0]++'

Hi nezabudka,
Nice approach. My code counts the number of lines output and ignores the value originally found in the "T" line field #2; your code subtracts the number of duplicates found.

If...

awk -F, '/^T/ {for(i in A) sum+=(A[i]-1); $2=$2-sum} !A[$0]++' file

I'm always glad to have helped. With the sample data you provided, the following would also work:
/usr/xpg4/bin/awk '
BEGIN { FS = OFS = ","
}
$1 == "D" {
if($0 in a)
next
a[$0]...

Your description and code are not clear enough to be sure that this is what you want, but it works with the sample data provided:
awk '
BEGIN { FS = OFS = ","
}
$1 == "D" {
if($2 in a)
next...

That depends - among other things - on what is in ~/.profile. One conceivable cause could be: $# is the number of (commandline) parameters the current process got. i.e. Consider this script:

#!...

when you say that it doesn't run, what does it mean? Any error messages? Anything get output?
Please post the first 10 lines of the script using code tags.

Methinks you mean "indent", and you want to suppress all entries with one or two spaces indentation? Why is auto_joba-bx (three leading spaces) missing in your sample result? How far would awk...

Hello green_k,

\\( means escape \ to remove its special meaning. If you will put ( without \ will be treated as sub's starting ( parenthesis and it will give error.

Thanks,
R. Singh

It is because awk substitutes \ in strings. For example
nawk 'BEGIN {print "\a"}' </dev/null
nawk 'BEGIN {print "\b"}' </dev/nullSo within " " you need \\ for a literal \
Therefore, you better...

Thanks, RavinderSingh13, for this explanation. Small, nit-picking side remark: Nothing can be "greater than" AND "equal to" something, that's mutually exclusive. "Greater than or equal" would...

Hello green_k,

Welcome to UNIX and Linux forums, hope you will enjoy sharing and learning knowledge here. Following explanation may help you in your question.

awk 'NF==1{ ...